C：计算2个浮点之间的距离，取模12
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我需要一个函数dist（a，b）// 0≤a，b <12，该函数使用模12返回最短（绝对值+ ve）距离ala时钟算术。
例如
dist( 1, 2 )
= dist( 2, 1 )
= dist( 11, 0 )
= dist( 0, 11 )
= dist( 0.5, 11.5 )
= 1
没有找到相关结果
已邀请:
3 个回复
拟蓬
float distMod12(float a,float b) { float diff = fabs( b - a ); return ( diff < 6 ) ? diff : 12 - diff; }完整的代码在这里列出：http://ideone.com/XxRIw蓄荣糖些
#include <math.h> #include <stdio.h> double min( double a, double b ) { return a < b ? a : b; } double dist( double a, double b ) { return min( fmod( 12+b-a, 12 ), fmod( 12+a-b, 12 ) ); } int main() { printf(\"%f\\n\", dist(1, 2)); printf(\"%f\\n\", dist(2, 1)); printf(\"%f\\n\", dist(11, 0)); printf(\"%f\\n\", dist(0, 11)); printf(\"%f\\n\", dist(0.5, 11.5)); return 0; }double dist( double a, double b ) { double diff = fmod( 12+a-b, 12 ); return diff <= 6 ? diff : 12-diff; }委婪绷冗诉
float dist( float a, float b ){ float amod, bmod; amod = fmod( a, 12 ); bmod = fmod( b, 12 ); if( amod < bmod ) return dist( bmod, amod ); return min( amod-bmod, bmod-amod+12 ); }