来自非常大的int C＃的模数
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我遇到了来自31个字符的整数模的问题。似乎错了
Int64 convertedNumber = Int64.Parse(mergedNumber);
Value was either too large or too small for an Int64. (Overflow Exception)
class GeneratorRachunkow {
private static string numerRozliczeniowyBanku = \"11111155\"; // 8 chars
private static string identyfikatorNumeruRachunku = \"7244\"; // 4 chars
private static string stalaBanku = \"562100\"; // 6 chars
public static string generator(string pesel, string varKlientID) {
string peselSubstring = pesel.Substring(pesel.Length - 5); // 5 chars (from the end of the string);
string toAttach = varKlientID + peselSubstring;
string indywidualnyNumerRachunku = string.Format(\"{0}\", toAttach.ToString().PadLeft(13, \'0\')); // merging pesel with klient id and adding 0 to the begining to match 13 chars
string mergedNumber = numerRozliczeniowyBanku + identyfikatorNumeruRachunku + indywidualnyNumerRachunku + stalaBanku; // merging everything -> 31 chars
Int64 convertedNumber = Int64.Parse(mergedNumber);
Int64 modulo = MathMod(convertedNumber, 97);
Int64 wynik = 98 - modulo;
string wynikString = string.Format(\"{0}\", wynik.ToString().PadLeft(2, \'0\')); // must be 2 chars
indywidualnyNumerRachunku = wynikString + numerRozliczeniowyBanku + identyfikatorNumeruRachunku + indywidualnyNumerRachunku;
return indywidualnyNumerRachunku;
}
private static Int64 MathMod(Int64 a, Int64 b) {
return (Math.Abs(a * b) + a) % b;
}
}
没有找到相关结果
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4 个回复
屠创氓读叔
的最大值为（打印时为19个字符）。您可能需要改用（在.NET 4中引入）：public static string generator(string pesel, string varKlientID) { // I have cut some code here to keep it short BigInteger convertedNumber; if (BigInteger.TryParse(mergedNumber , out convertedNumber)) { BigInteger modulo = convertedNumber % 97; // The rest of the method goes here... } else { // string could not be parsed to BigInteger; handle gracefully } } private static BigInteger MathMod(BigInteger a, BigInteger b) { return (BigInteger.Abs(a * b) + a) % b; }席酱
拈吉勉犬姆
static int ModString(string x, int y) { if (x.Length == 0) return 0; string x2 = x.Substring(0,x.Length - 1); // first digits int x3 = int.Parse(x.Substring(x.Length - 1)); // last digit return (ModString(x2, y) * 10 + x3) % y; }自1.1版以来，此版本应可用于所有版本的.NET，而无需BigInteger。蹄寄噬非芹