获取数组的大小
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我有一些代码，需要使用for循环从数组中读取变量。
int size=sizeof names;
NSLog(@\"thelast one is %d\",size);
NSString *usersName=userName.text;
NSString *usersPass=passWord.text;
for (i=0; i<=size;i++){
NSString *namesArray=[names objectAtIndex:i];
NSString *passArray=[pass objectAtIndex:i];
NSLog(@\"namesArray %@\",namesArray);
NSLog(@\"passArray %@\",passArray);
if([namesArray isEqualToString:usersName]){
userValid=1;
NSLog(@\"The content of arry4 is %@\",namesArray);
}
if([passArray isEqualToString:usersPass]){
passValid=1;
NSLog(@\"The content of arry4 is %@\",passArray);
}
else {
userValid=0;
passValid=0;
}
}
没有找到相关结果
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5 个回复
膛嵌墒缅欠
。拈吉勉犬姆
炉挤仙挟
，该方法返回returns4ѭ。 另外，如果我没记错的话，可以使用ѭ5，循环遍历这些元素，在Java中也可用。for (MyClass *element in myArray) { NSLog(@\"%@\", element); }中存储了多少个元素，而是一个NSArray实例的字节大小。贡炮逗握惫
NSString *userName = userName.text; NSString *userPass = passWord.text; // Use a block enumerator NSUInteger nameIdx = [names indexOfObjectPassingTest:^(id obj, NSUInteger idx, BOOL *stop) { return ([obj isEqualToString:userName]); }]; // Is the name in the array if (nameIdx == NSNotFound) { // Name not in array - so set to zero userValid = 0; passValid = 0; } else { userValid = 1; // See if the corresponding password is correct NSString password = [pass objectAtIndex:nameIdx]; if (![password isEqualToString:userPass]) { passValid = 0; } else { passValid = 1; }玩翁文醚碱
NSString *userName = userName.text; NSString *userPass = passWord.text; BOOL userValid = NO; BOOL passValid = NO; int index = 0; for (NSString *eachName in namesArray) { if ([eachName isEqualToString:userName) { userValid = YES: if ([[passArray objextAtIndex:index] isEqualToString:passWord) { passValid = YES; } break; } index += 1; }