将Double转换为二进制表示形式？

Long.toBinaryString(Double.doubleToRawLongBits(d))

System.out.println(\"0:                0b\" + Long.toBinaryString(Double.doubleToRawLongBits(0D)));
System.out.println(\"1:                0b\" + Long.toBinaryString(Double.doubleToRawLongBits(1D)));
System.out.println(\"2:                0b\" + Long.toBinaryString(Double.doubleToRawLongBits(2D)));
System.out.println(\"2^900:            0b\" + Long.toBinaryString(Double.doubleToRawLongBits(Math.pow(2, 900))));
System.out.println(\"Double.MAX_VALUE: 0b\" + Long.toBinaryString(Double.doubleToRawLongBits(Double.MAX_VALUE)));

/*
    prints:
    0:                0b0
    1:                0b11111111110000000000000000000000000000000000000000000000000000
    2:                0b100000000000000000000000000000000000000000000000000000000000000
    2^900:            0b111100000110000000000000000000000000000000000000000000000000000
    Double.MAX_VALUE: 0b111111111101111111111111111111111111111111111111111111111111111
*/

public String toBinary(double d, int precision) {
    long wholePart = (long) d;
    return wholeToBinary(wholePart) + \'.\' + fractionalToBinary(d - wholePart, precision);
}

private String wholeToBinary(long l) {
    return Long.toBinaryString(l);
}

private String fractionalToBinary(double num, int precision) {
    StringBuilder binary = new StringBuilder();
    while (num > 0 && binary.length() < precision) {
        double r = num * 2;
        if (r >= 1) {
            binary.append(1);
            num = r - 1;
        } else {
            binary.append(0);
            num = r;
        }
    }
    return binary.toString();
}

BigInteger bigNum = new BigInteger(sYourNum);
System.out.println( bigNum.toString(2) );

java.math.BigInteger

toString(int radix)