如何检查iphone中已解析元素的条件
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从我项目中的Json解析中，我正在获取这些元素...
执行指令：
NSArray *feed3 = (NSArray *)[feed valueForKey:@\"type\"];
NSLog(@\" %@\",feed3);
if(type==staus){
//do some thing
}
没有找到相关结果
已邀请:
2 个回复
凰葱崎济邯
是解析另一个问题中列出的JSON数据后JSON解析器返回的对象。在这种情况下：* the top level object is an array * every element in the array is an object/dictionary representing news * this object/dictionary contains the following keys: * application (object/dictionary with two keys: id, name) * id (number) * name (string) * created_time (string) * from (object/dictionary with two keys: id, name) * id (number) * name (string) * icon (string) * id (string) * likes (object/dictionary with two keys: count, data) * count (number) * data (array) * every element in the array is an object/dictionary * this object/dictionary has two keys (id, name) * id (number) * name (string) * link (string) * name (string) * picture (string) * properties (array of objects/dictionaries) * type (string) * updated_time (string)for (NSDictionary *news in feed3) { NSString *type = [news objectForKey:@\"type\"]; if ([type isEqualToString:@\"status\"]) { … } else if ([type isEqualToString:@\"photo\"]) { … } else if ([type isEqualToString:@\"link\"]) { … } else if ([type isEqualToString:@\"video\"]) { … } }代替：是在中声明的方法，它用于在给定相应键的情况下获取存储在字典中的对象。是KVC方法，并具有其他目的。特别是，当您不期望一个数组时，它可以返回一个数组！壬驴拿歪竞
for(int index = 0 ; index < [feed3 count] ; index++) { NSString* tempString = [feed3 objectAtIndex:index]; if([tempString isEqualToString:@\"status\"]) { //Get value for status from value array } else if([tempString isEqualToString:@\"photo\"]) { //Get value for photo from value array } else if([tempString isEqualToString:@\"link\"]) { //Get value for link from value array } else if([tempString isEqualToString:@\"video\"]) { //Get value for video from value array } }