如何在Java中进行URL解码?

| 在Java中,我想将其转换为:
https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest_type
对此:
https://mywebsite/docs/english/site/mybook.do&request_type
这是我到目前为止的内容:
class StringUTF 
{
    public static void main(String[] args) 
    {
        try{
            String url = 
               \"https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do\" +
               \"%3Frequest_type%3D%26type%3Dprivate\";

            System.out.println(url+\"Hello World!------->\" +
                new String(url.getBytes(\"UTF-8\"),\"ASCII\"));
        }
        catch(Exception E){
        }
    }
}
但这行不通。这些
%3A
%2F
格式叫什么?如何转换它们?     
已邀请:
这与字符编码(例如UTF-8或ASCII)无关。您所拥有的字符串经过URL编码。这种编码与字符编码完全不同。 尝试这样的事情:
try {
    String result = java.net.URLDecoder.decode(url, StandardCharsets.UTF_8.name());
} catch (UnsupportedEncodingException e) {
    // not going to happen - value came from JDK\'s own StandardCharsets
}
Java 10在API中添加了对ѭ6的直接支持,这意味着无需捕获UnsupportedEncodingException:
String result = java.net.URLDecoder.decode(url, StandardCharsets.UTF_8);
请注意,字符编码(例如UTF-8或ASCII)决定了字符到原始字节的映射。有关字符编码的良好介绍,请参见本文。     
您得到的字符串是
application/x-www-form-urlencoded
编码。 使用URLDecoder将其转换为Java String。
URLDecoder.decode( url, \"UTF-8\" );
    
这已经被回答过(尽管这个问题是第一个!):   \“您应该使用java.net.URI来执行此操作,因为URLDecoder类进行x-www-form-urlencoded解码是错误的(尽管名称,它用于表单数据)。\” 基本上:
String url = \"https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest_type\";
System.out.println(new java.net.URI(url).getPath());
会给你:
https://mywebsite/docs/english/site/mybook.do?request_type
    
%3A
%2F
是URL编码的字符。使用此Java代码将它们转换回
:
/
String decoded = java.net.URLDecoder.decode(url, \"UTF-8\");
    
 try {
        String result = URLDecoder.decode(urlString, \"UTF-8\");
    } catch (UnsupportedEncodingException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    
public String decodeString(String URL)
    {

    String urlString=\"\";
    try {
        urlString = URLDecoder.decode(URL,\"UTF-8\");
        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block

        }

        return urlString;

    }
    
我使用apache commons
String decodedUrl = new URLCodec().decode(url);
默认字符集为
UTF-8
    
import java.io.UnsupportedEncodingException;
import java.net.URISyntaxException;

public class URLDecoding { 

    String decoded = \"\";

    public String decodeMethod(String url) throws UnsupportedEncodingException
    {
        decoded = java.net.URLDecoder.decode(url, \"UTF-8\"); 
        return  decoded;
//\"You should use java.net.URI to do this, as the URLDecoder class does x-www-form-urlencoded decoding which is wrong (despite the name, it\'s for form data).\"
    }

    public String getPathMethod(String url) throws URISyntaxException 
    {
        decoded = new java.net.URI(url).getPath();  
        return  decoded; 
    }

    public static void main(String[] args) throws UnsupportedEncodingException, URISyntaxException 
    {
        System.out.println(\" Here is your Decoded url with decode method : \"+ new URLDecoding().decodeMethod(\"https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest_type\")); 
        System.out.println(\"Here is your Decoded url with getPath method : \"+ new URLDecoding().getPathMethod(\"https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest\")); 

    } 

}
您可以明智地选择方法:)     

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