OpenJPA条件Builder嵌套对象属性访存
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OpenJPA中是否可以通过CriteriaBuilder获得嵌套对象属性的任何方法？
这是一个小案件。
@Entity
public class X {
private Object Y;
// getters, setters...
}
@Entity
public class Y {
private String Z;
// getters, setters...
}
@PersistenceContext
private EntityManager entityManager;
//.....
Root<X> rootObj = criteriaBuilder.from(X.class);
CriteriaQuery<X> select;
String param1 = X.getY().getZ();
// initializing predicate, default value is TRUE
Predicate predicate1 = criteriaBuilder.isNull(null);
// construct search predicate which fails miserably due to IllegalArgumentExecption
if (X != null) {
predicate1 = criteriaBuilder.and(predicate1, criteriaBuilder.equal(rootObj.<String> get(\"Y.Z\"), param1));}
get(\"Y.Z\")
没有找到相关结果
已邀请:
2 个回复
漂汀拦
我真的不知道是否有更优雅的解决方案。链眷克袒姜
private Path<T> getPath(Root<T> root, String attributeName) { Path<T> path = root; for (String part : attributeName.split(\"\\\\.\")) { path = path.get(part); } return path; }