读取二进制文件并将所有数据存储到结构数组中
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我需要编写一个简单的测量转换程序的程序。
该程序首先询问用户二进制文件的名称(单位转换数据),打开文件并设置数组。
我的结构:
struct unit {
char name[NAME_LEN];
char abbrev[ABBREV_LEN];
char class[CLASS_LEN];
double standard;
};
和我的功能:
int fread_units(int unit_max,struct unit units[], int *unit_sizep)
{
FILE *filep;
struct unit data;
int i, status;
char fullname[10];
/* Gets database of units from file */
printf(\"Enter name of binary file> \");
scanf(\"%s\", fullname);
strcat(fullname, \".bin\");
i = 0;
filep = fopen(fullname, \"rb\");
//fseek (filep , 0 , SEEK_END);
for (status = fread(&data, sizeof( struct unit ), 1, filep);
status == 1 && i < unit_max;
status = fread(&data, sizeof( struct unit ), 1, filep)){
units[i++] = data;
}
printf(\"\\n%f\", units[3].standard);
/* Issue error message on premature exit */
if (status == 0) {
printf(\"\\n*** Error in data format ***\\n\");
printf(\"*** Using first %d datavalues ***\\n\",i);
}
else if (status != EOF) {
printf(\"\\n*** Error: too much data in file ***\\n\");
printf(\"*** Using first %d data values ***\\n\", i);
}
/* Send back size of used portion of array */
*unit_sizep = i;
if(status == 4)
status = 1;
else if (status != EOF)
status = 0;
fclose(filep);
return(status);
}
根据这本书,“ 2”足以将所有数据存储到一个结构中。
但这对我不起作用...
输出:
*** Error in data format ***
*** Using first 4 datavalues ***
To convert 25 kilometers to miles, you would enter
> 25 kilometers miles
or, alternatively,
> 25 km mi
> 25 km mi
Attempting conversion of 25.0000 km to mi . . .
Unit kmnot in database
Enter a conversion problem or q to quit.
>
我的units.bin文件;
miles mi distance 1609.3
kilometers km distance 1000
yards yd distance 0.9144
meters m distance 1
quarts qt liguid_volume 0.94635
liters l liquid_volume 1
gallons gal liquid_volume .7854
millimeters ml liquid_volume 0.001
kilograms kg mass 1
grams g mass 0.001
slugs slugs mass 0.14594
没有找到相关结果
已邀请:
1 个回复
抬澈帅沮
和我的for循环;