选择一个选择器会导致UIbutton图像更改

| 我一直在寻找一种构建UIpicker的方法,选择该行将导致UIbutton图像的更改。通常的if,else方法更改按钮似乎在这里不起作用。有谁知道该怎么做? 这是我找到并正在使用的模型代码。我该如何修改? 非常感谢。
@synthesize button;
// Implement viewDidLoad to do additional setup after loading the view, typically from a nib.
- (void)viewDidLoad {
    [super viewDidLoad];

    arrayColors = [[NSMutableArray alloc] init];

    [arrayColors addObject:@\"Orange\"];
    [arrayColors addObject:@\"Yellow\"];
    [arrayColors addObject:@\"Green\"];
    [arrayColors addObject:@\"Blue\"];
    [arrayColors addObject:@\"Indigo\"];
    [arrayColors addObject:@\"Violet\"];
}


- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning]; // Releases the view if it doesn\'t have a superview
    // Release anything that\'s not essential, such as cached data
}


- (void)dealloc {
    [arrayColors release];
    [super dealloc];
}

#pragma mark -
#pragma mark Picker View Methods

- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)thePickerView {

    return 1;
}

- (NSInteger)pickerView:(UIPickerView *)thePickerView numberOfRowsInComponent:(NSInteger)component {

    return [arrayColors count];
}

- (NSString *)pickerView:(UIPickerView *)thePickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component {

    return [arrayColors objectAtIndex:row];
}

- (void)pickerView:(UIPickerView *)thePickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component {

    NSLog(@\"Selected Color: %@. Index of selected color: %i\", [arrayColors objectAtIndex:row], row);
}

@end
    
已邀请:
        在didSelectRow方法中,您可以检查以查看选择了哪个索引。然后从那里创建if语句。如果由于某种原因不能正常工作,那么我将创建一个NSTimer来每1秒检查一次值。如果选择器的值更改,那么更改图像按钮吗?多数民众赞成在第一件事突然出现在我的脑海。
- (void)pickerView:(UIPickerView *)thePickerView didSelectRow:(NSInteger)row inComponent:(NSInteger )component {


    //component is the entire colomn on a picker \"all of your colors\"
    if (component == 0) {

                //row is the selected item in the colomn \"orange\"
        if (row == 0) {
              //color was selected
                     //change image here 
                 }

    }



}
    

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