翻转硬币问题
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我一直在玩，并编写了这段小代码。我试图翻转硬币定义的次数，然后计算我得到多少尾巴和头。所以这里是：
private void Start_Click(object sender, EventArgs e)
{
int headss = 0;
int tailss = 0;
int random2, g;
string i = textBox1.Text;
int input2, input;
bool NumberCheck = int.TryParse(i, out input2);
if (textBox1.Text == String.Empty) // check for empty string, when true
MessageBox.Show(\"Enter a valid number between 0 and 100000.\");
else // check for empty string, when false
if (!NumberCheck) // number check, when false
{
textBox1.Text = String.Empty;
MessageBox.Show(\"Enter a valid number between 0 and 100000.\");
}
else
{
input = Convert.ToInt32(textBox1.Text);
for (g = 0; g < input; g++)
{
Random random = new Random();
random2 = random.Next(2);
if (random2 == 0)
{
headss++;
}
else if (random2 == 1)
{
tailss++;
}
}
}
heads.Text = Convert.ToString(headss);
tails.Text = Convert.ToString(tailss);
}
Random random = new Random();
没有找到相关结果
已邀请:
4 个回复
席陋临拈
for (g = 0; g < input; g++) { Random random = new Random(); random2 = random.Next(2); }private Random randomGenerator = new Random(); private void Start_Click(object sender, EventArgs e) { // ... for (g = 0; g < input; g++) { random2 = randomGenerator.Next(2); } // ... }耐扫鹤胶鞭
蕉衫
辩谷变充
。此代码将计算硬币被翻转了多少次。它将以3个连续的HEADS结尾。private RandomGenerator rgen = new RandomGenerator (); public void run () { int value = 0; int total = 0; while (value != 3) { String coinFlip = rgen.nextBoolean() ? \"HEADS\" : \"TAILS\"; println (coinFlip); if (coinFlip == \"HEADS\") { value+=1; } else { value=0; } total +=1; } println (\"It took \"+total+\" flips to get 3 consecutive heads\"); }