如何在appfuse中只显示子菜单项
（无论如何，我认为这是来自appfuse。我并不总是清楚哪个框架仍属于哪个部分。）
我的
menu-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<MenuConfig>
<Displayers>
<Displayer name="Velocity" type="net.sf.navigator.displayer.VelocityMenuDisplayer"/>
</Displayers>
<Menus>
<Menu name="MainMenu" title="mainMenu.title" page="/mainmenu">
<Item name="Foo" title="menu.foo" page="/foo"/>
<Item name="Bar" title="menu.bar" page="/bar"/>
<Item name="Baz" title="menu.baz" page="/baz"/>
</Menu>
<Menu name="OtherMenu" title="otherMenu.title" page="/othermenu">
<Item name="Squee" title="menu.squee" page="/squee"/>
<Item name="Lorem" title="menu.lorem" page="/lorem"/>
</Menu>
<Menu name="UserMenu" title="menu.user" description="User Menu" page="mainmenu.editprofile" roles="ROLE_ADMIN,ROLE_USER"/>
<Menu name="Logout" title="user.logout" page="/logout" roles="ROLE_ADMIN,ROLE_USER"/>
</Menus>
</MenuConfig>
<%@ include file="/common/taglibs.jsp"%>
<menu:useMenuDisplayer name="Velocity" config="cssHorizontalMenu.vm" permissions="rolesAdapter">
<ul class="tabs menuList">
<menu:displayMenu name="MainMenu"/>
</ul>
</menu:useMenuDisplayer>
<ul>
<li>Foo</li>
<li>Bar</li>
<li>Baz</li>
</ul>
<ul>
<li>Main Menu</li>
<li>
<ul>
<li>Foo</li>
<li>Bar</li>
<li>Baz</li>
</ul>
</li>
</ul>
没有找到相关结果
已邀请:
1 个回复
导力疵谜
#macro( displayCssMenu $menu ) #if ($displayer.isAllowed($menu)) #set ($count = $count + 1) ## set menu title #set ($title = $displayer.getMessage($menu.title)) #if (!$menu.url) #set ($url="javascript:void(0)") #else #set ($url=$menu.url) #end ## create a single menu item #set ($itemClass = "") #if (!$menu.parent) #set ($itemClass = "mainItem") #end #set ($img = "") #if ($menu.image) #set ($img = "<img alt='$menu.image' class='icon setImageMenu $menu.image'/>") #end #if ($menu.components.size() == 0) #if ($count == $renderedChildren) <li class="last"> #else <li> #end #if ($menu.name == $currentMenu) <a href="$url" title="$title" class="current $itemClass" #if($menu.target)target="$menu.target" #end#if($menu.width)style="width: ${menu.width}px"#end>$img ${title}</a> #else <a href="$url" title="$title" class="$itemClass" #if($menu.target)target="$menu.target" #end#if($menu.width)style="width: ${menu.width}px"#end>$img ${title}</a> #end #else ## create multiple menu items in a menu #if ($menu.components.size() > 0) #set ($hasViewableChildren = false) #set ($renderedChildren = 0) #foreach ($menuIt in $menu.components) #if ($displayer.isAllowed($menuIt)) #set($hasViewableChildren = true) #set($renderedChildren = $renderedChildren + 1) #end #end #end <li#if ($hasViewableChildren) class="menubar"#end> <a href="$url" title="$title" #if ($menu.name == $currentMenu) class="current $itemClass" #else class="$itemClass" #end#if($menu.target)target="$menu.target" #end#if($menu.width)style="width: ${menu.width}px"#end>$img ${title}</a> #end #if ($menu.components.size() > 0) #if ($hasViewableChildren) <ul> #end #set ($count = 0) #foreach ($menuIt in $menu.components) #displayCssMenu($menuIt) #end #if ($hasViewableChildren && ($count == $renderedChildren)) </li> #else </ul> #if ($count > $renderedChildren) </li> #end #end #else </li> #if ($count == $menu.parent.components.size()) </ul> #end #end #end #end #displayCssMenu($menu)#if ($menu.components.size() == 0 && $menu.parent) #if ($count == $renderedChildren) <li class="last"> #else <li> #end bla.. bla... bla.. bla... #end #if ($menu.components.size() > 0) #if ($hasViewableChildren) <ul> #end bla.. bla... #else #if ($menu.parent) </li> #end #if ($count == $menu.parent.components.size()) </ul> #end #end