重叠与Python中的finditer（）匹配
我正在使用正则表达式来匹配文本中的圣经经文参考。目前的正则表达式是
REF_REGEX = re.compile('''
(?<!w) # Not preceded by any words
(?P<quote>q(?:uote)?s+)? # Match optional 'q' or 'quote' followed by many spaces
(?P<book>
(?:(?:[1-3]|I{1,3})s*)? # Match an optional arabic or roman number between 1 and 3.
[A-Za-z]+ # Match any alphabetics
).? # Followed by an optional dot
(?:
s*(?P<chapter>d+) # Match the chapter number
(?:
[:.](?P<startverse>d+) # Match the starting verse number, preceded by ':' or '.'
(?:-(?P<endverse>d+))? # Match the optional ending verse number, preceded by '-'
)? # Verse numbers are optional
)
(?:
s+(?: # Here be spaces
(?:froms+)|(?:ins+)|(?P<lbrace>()) # Match 'from[:space:]', 'in[:space:]' or '('
s*(?P<version>w+) # Match a word preceded by optional spaces
(?(lbrace))) # Close the '(' if found earlier
)? # The whole 'in|from|()' is optional
''', re.IGNORECASE | re.VERBOSE | re.UNICODE)
"jn 3:16": (None, 'jn', '3', '16', None, None, None),
"matt. 18:21-22": (None, 'matt', '18', '21', '22', None, None),
"q matt. 18:21-22": ('q ', 'matt', '18', '21', '22', None, None),
"QuOTe jn 3:16": ('QuOTe ', 'jn', '3', '16', None, None, None),
"q 1co13:1": ('q ', '1co', '13', '1', None, None, None),
"q 1 co 13:1": ('q ', '1 co', '13', '1', None, None, None),
"quote 1 co 13:1": ('quote ', '1 co', '13', '1', None, None, None),
"quote 1co13:1": ('quote ', '1co', '13', '1', None, None, None),
"jean 3:18 (PDV)": (None, 'jean', '3', '18', None, '(', 'PDV'),
"quote malachie 1.1-2 fRom Colombe": ('quote ', 'malachie', '1', '1', '2', None, 'Colombe'),
"quote malachie 1.1-2 In Colombe": ('quote ', 'malachie', '1', '1', '2', None, 'Colombe'),
"cinq jn 3:16 (test)": (None, 'jn', '3', '16', None, '(', 'test'),
"Q IIKings5.13-58 from wolof": ('Q ', 'IIKings', '5', '13', '58', None, 'wolof'),
"This text is about lv5.4-6 in KJV only": (None, 'lv', '5', '4', '6', None, 'KJV'),
"Found in 2 Cor. 5:18-21 ( Ministers": (None, '2 Cor', '5', '18', '21', None, None),
(None, 'in', '2', None, None, None, None)
没有找到相关结果
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薄响
）似乎不是可选的。删除它将匹配最后一位。ref_regex = re.compile(''' (?<!w) # Not preceeded by any words ((?i)q(?:uote)?s+)? # Match 'q' or 'quote' followed by many spaces ( (?:(?:[1-3]|I{1,3})s*)? # Match an arabic or roman number between 1 and 3. [A-Za-z]+ # Match many alphabetics ).? # Followed by an optional dot (?: s*(d+) # Match the chapter number (?: [:.](d+) # Match the verse number (?:-(d+))? # Match the ending verse number ) # <-- no '?' here ) (?: s+ (?: (?i)(?:froms+)| # Match the keyword 'from' or 'in' (?:ins+)| (?P<lbrace>() # or stuff between (...) )s*(w+) (?(lbrace))) )? ''', re.X | re.U)标志。） 如果你真的需要重叠匹配，你可以使用前瞻。一个简单的例子是>>> rx = re.compile('(.)(?=(.))') >>> x = rx.finditer("abcdefgh") >>> [y.groups() for y in x] [('a', 'b'), ('b', 'c'), ('c', 'd'), ('d', 'e'), ('e', 'f'), ('f', 'g'), ('g', 'h')]