如何反序列化JSON数据树？
|
假设我的JSON数据格式为：（某种树数据：）
{
\“ nodeData \”：
[
\“ nodeObject \”：
{
\“ nodeName \”：\“节点1 \”，
\"nodeChildren\":
[
\"nodeObject\":
{
\"nodeName\": \"Node 1-1\"
},
\"nodeObject\":
{
\"nodeName\": \"Node 1-2\"
},
\"nodeObject\":
{
\"nodeName\": \"Node 1-3\",
\"nodeChildren\":
[
\"nodeObject\":
{
\"nodeName\": \"Node 1-3-1\"
}
]
},
\"nodeObject\":
{
\"nodeName\": \"Node 1-4\"
},
\"nodeObject\":
{
\"nodeName\": \"Node 1-5\",
}
]
},
\"nodeObject\":
{
\"nodeName\": \"Node 2\",
},
\"nodeObject\":
{
\"nodeName\": \"Node 3\",
}
[DataContract]
internal class nodeObject
{
[DataMember]
public string nodeName;
[DataMember]
public nodeObject nodeChildren;
}
var jsonSerializer = new DataContractJsonSerializer(typeof(List<nodeObject>));
var nodes = jsonSerializer.ReadObject(e.Result) as List<nodeObject>;
this.listBox1.ItemsSource = nodes;
没有找到相关结果
已邀请:
3 个回复
俺呵誓放胳
[ \"nodeObject\": { \"nodeName\": //... ][ {\"nodeName\": \"Node-1-1\"}, {\"nodeName\": \"Node-1-2\"} /* ... */ ]乏摩纶誊伟
{ \"nodeData\": [ \"nodeObject\", { \"nodeName\": \"Node 1\", \"nodeChildren\": [ \"nodeObject\", { \"nodeName\": \"Node 1-1\" }, \"nodeObject\", { \"nodeName\": \"Node 1-2\" }, \"nodeObject\", { \"nodeName\": \"Node 1-3\", \"nodeChildren\": [ \"nodeObject\", { \"nodeName\": \"Node 1-3-1\" } ] }, \"nodeObject\", { \"nodeName\": \"Node 1-4\" }, \"nodeObject\", { \"nodeName\": \"Node 1-5\" } ] }, \"nodeObject\", { \"nodeName\": \"Node 2\" }, \"nodeObject\", { \"nodeName\": \"Node 3\" } ] }完趣镐
DataContractJsonSerializer json = new DataContractJsonSerializer(typeof(List<Client>)); System.IO.MemoryStream clientListStream = new System.IO.MemoryStream(); clientListStream.Write(System.Text.Encoding.UTF8.GetBytes(e.Result), 0, e.Result.Length); List<Client> Clients = json.ReadObject(clientListStream) as List<Client>; dgMain.ItemsSource = Clients;