如何一次选择多个联系人？
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我使用以下代码将电话簿联系人检索到我的应用程序：
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Intent contactPickerIntent = new Intent(Intent.ACTION_PICK,
Contacts.CONTENT_URI);
startActivityForResult(contactPickerIntent, CONTACT_PICKER_RESULT);
}
没有找到相关结果
已邀请:
2 个回复
臂哦
缝皋
people = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null); int position=0; Cursor q=db.query(mProfile,new String[]{\"person_name\"},\"person_name\"+\"!=\'\"+null+\"\'\",null,null, null, null); people.moveToFirst(); int nameFieldColumnIndex = people.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME); while(!people.isAfterLast()) { Cursor o=db.query(mProfile,new String[]{\"person_name\"},\"person_name\"+\"=\'\"+people.getString(nameFieldColumnIndex)+\"\'\",null,null, null, null); if(!(o.getCount()>0)) { mConname.add(position, people.getString(nameFieldColumnIndex)); try{ String contactId = people.getString(people.getColumnIndex(ContactsContract.Contacts._ID)); String hasPhone = people.getString(people.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); if ( hasPhone.equalsIgnoreCase(\"1\")) hasPhone = \"true\"; else hasPhone = \"false\" ; if (Boolean.parseBoolean(hasPhone)) { Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID +\" = \"+ contactId,null, null); while (phones.moveToNext()) { String phoneNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); mConno.add(position,phoneNumber); } phones.close(); } if(hasPhone==\"false\") { mConname.remove(position); } else position++; } catch(Exception e) { } } people.moveToNext(); }