如何使用带有boost.Spirit的嵌套括号来解析表达式？
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我需要解析包含键/值对和键/子表达式对的1行表达式，例如：
123=a 456=b 789=(a b c) 111=((1=a 2=b 3=c) (1=x 2=y 3=z) (123=(x y z))) 666=evil
\"a b c\"
(1=a 2=b 3=c) (1=x 2=y 3=z) (123=(x y z))
(1=a 2=b 3=c
#include <map>
#include <string>
#include <boost/spirit/include/classic.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/include/std_pair.hpp>
namespace qi = boost::spirit::qi;
void main()
{
auto value = +qi::char_(\"a-zA-Z_0-9\");
auto key = qi::char_(\"a-zA-Z_\") >> *qi::char_(\"a-zA-Z_0-9\");
qi::rule<std::string::iterator, std::pair<std::string, std::string>()> pair = key >> -(\'=\' >> value);
qi::rule<std::string::iterator, std::map<std::string, std::string>()> query = pair >> *((qi::lit(\';\') | \'&\') >> pair);
std::string input(\"key1=value1;key2;key3=value3\"); // input to parse
std::string::iterator begin = input.begin();
std::string::iterator end = input.end();
std::map<std::string, std::string> m; // map to receive results
bool result = qi::parse(begin, end, query, m); // returns true if successful
}
没有找到相关结果
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倪蕊悲潍
qi::rule<std::string::iterator, std::pair<std::string, std::string>()> pair = key >> -( \'=\' >> ( \'(\' >> raw[query] >> \')\' | value ) ) ;qi::rule<std::string::iterator, std::pair<std::string, std::string>()> pair = key >> -( \'=\' >> ( raw[\'(\' >> query >> \')\'] | value ) ) ;