如何检测Zend Framework表单上按下了哪个提交按钮？
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我有一个带有两个提交按钮的Zend Framework表单
$changes = new Zend_Form_Element_Submit(\'save_changes\');
$changes->setLabel(\'Save Changes\');
$delete = new Zend_Form_Element_Submit(\'delete\');
$delete->setLabel(\'Delete\');
<input type=\"submit\" name=\"save_changes\" id=\"user_save_changes\" value=\"Save Changes\" >
<input type=\"submit\" name=\"delete\" id=\"user_delete\" value=\"Delete\" >
没有找到相关结果
已邀请:
5 个回复
屠创氓读叔
由于将仅提交单击按钮的值。 通常，您将两个按钮都命名为相同的名称（例如，动作），然后将 您想要执行的操作的价值。不幸的是，这不能很好地工作 与IE。检查此页面以获取有关多个解决方案的更多信息 提交按钮。埠仙俊
if ($form->save_changes->isChecked()) { // Saving ... else if ($form->delete->isChecked()) { // Removing ...bab
if($this->getRequest()->getPost(\'save_changes\'){ //Code here } if($this->getRequest()->getPost(\'delete\'){ //Code here }if($this->getRequest()->getPost(\'save_changes\'){ //once you load this will become true because you didn\'t click this }else{ //once you load this page this will become true because you didn\'t click the save_changes submit button }贸会
$data = $this->getRequest()->getPost(); if (array_key_exists(\'save_changes\', $data)) { .. } else if (array_key_exists(\'delete\', $data)) { .. }温拎凯玛
$formData = $this->getRequest()->getPost(); if($formData[\'submit\']==\'save_changes\'){ // echo \"save chanes\" ; } if($formData[\'submit\']==\'delete\'){ // echo \"delete\";}