Python-比较理解中的两个列表

list_1 = [1, 2, 3, 4, 5, 6]
list_2 = [1, 2, 3, 0, 5, 6]

# Print all items from list_1 that are not in list_2 ()
print(*[item for item in list_1 if item not in list_2], sep=\'\\n\')

# Print all items from list_1 that differ from the item at the same index in list_2
print(*[x for x, y in zip(list_1, list_2) if x != y], sep=\'\\n\')

# Print all items from list_2 that differ from the item at the same index in list_1
print(*[y for x, y in zip(list_1, list_2) if x != y], sep=\'\\n\')

for a, b in zip(list1, list2):
    if a != b:
       print(a, \"is different from\", b) 

[print(a, \"is different from\", b) for a, b in zip(list1, list2) if a!=b]

set

s.symmetric_difference(t)   s ^ t   new set with elements in either s or t but not both

>>> L1 = [\'a\', \'b\', \'c\', \'d\']
>>> L2 = [\'b\', \'c\', \'d\', \'e\'] 
>>> S1 = set(L1)
>>> S2 = set(L2)
>>> difference = list(S1.symmetric_difference(S2))
>>> print difference
[\'a\', \'e\']
>>> 

>>> print list(set(L1).symmetric_difference(set(L2)))
[\'a\', \'e\']
>>> 

>>> [word for word in L1 if word not in L2] + [word for word in L2 if word not in L1]
[\'a\', \'e\']