如何在Servlet的jsp中使用doGet
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我正在尝试向Servlet发送一些内容,但我知道了
Etat HTTP 404 - /pdfreader/Services%20Web%20avec%20J2EE%20et%20.NET.pdf
--------------------------------------------------------------------------------
type Rapport d\'\'état
message /pdfreader/Services%20Web%20avec%20J2EE%20et%20.NET.pdf
description La ressource demandée (/pdfreader/Services%20Web%20avec%20J2EE%20et%20.NET.pdf) n\'est pas disponible.
我像这样从我的JSP调用它
<a href=\"/pdfreader/<%=filename/*le nom d\'un fichier pdf par exemple (jsp.pdf)*/ %>\"><%=bookName %> </a>
而我的servlet代码是
package com.search.ts;
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.net.URLDecoder;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class pdfreader
*/
@WebServlet(\"/pdfreader\")
public class pdfreader extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public pdfreader() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
String filename = URLDecoder.decode(request.getPathInfo(), \"UTF-8\");
//filename= request.getParameter(\"err\");
//String filename =(String) request.getAttribute(\"linkbook\");
File file = new File(\"F:/fichiers/\", filename);
response.setContentType(getServletContext().getMimeType(file.getName()));
response.setContentLength((int) file.length());
response.setHeader(\"Content-Disposition\", \"inline; filename=\\\"\" + file.getName() + \"\\\"\");
BufferedInputStream input = null;
BufferedOutputStream output = null;
try {
input = new BufferedInputStream(new FileInputStream(file));
output = new BufferedOutputStream(response.getOutputStream());
byte[] buffer = new byte[8192];
int length;
while ((length = input.read(buffer)) > 0) {
output.write(buffer, 0, length);
}
} finally {
if (output != null) try { output.close(); } catch (IOException ignore) {}
if (input != null) try { input.close(); } catch (IOException ignore) {}
}
}
}
当我创建servlet和jsp时,我在web-inf中没有得到任何web.xml(我使用eclipse)
所以我尝试创建一个
<?xml version=\"1.0\" encoding=\"UTF-8\"?>
<web-app>
<welcome-file-list>
<welcome-file>/vieu/indexS.jsp</welcome-file>
</welcome-file-list>
<servlet>
<javaee:description></javaee:description>
<javaee:display-name>pdfreader</javaee:display-name>
<servlet-name>pdfreader</servlet-name>
<servlet-class>pdfreader</servlet-class>
<jsp-file>/vieu/indexS.jsp</jsp-file>
</servlet>
<servlet-mapping>
<servlet-name>com.search.ts.pdfreader</servlet-name>
<url-pattern>/pdfreader/*</url-pattern>
</servlet-mapping>
</web-app>
有人知道为什么那行不通吗?
没有找到相关结果
已邀请:
2 个回复
辟官陡板休
URL中的斜杠“ 5”使其相对于域根。因此,当您的JSP在http:// localhost:8080 / contextname / vieu / indexS.jsp上运行时,该URL实际上指向http:// localhost:8080 / pdfreader / name.pdf。但是您希望它是http:// localhost:8080 / contextname / pdfreader / name.pdf!所以相应地修复它
二,servlet声明:
这是完全错误的。您需要对其进行如下注释:
第三,“ 9”缺少Servlet API版本声明,这导致容器回退到兼容性最低的方式,因此新的Servlet 3.0“ 10”注释将不再起作用。相应地修复它:
并从
中删除
和
声明。 a10ѭ(适当的!)不需要这些。
骇毖煽洁铂