SQL约束在两列中具有一个唯一值

Table A

CREATE TABLE MyNumbersTable (Value int);
-- You need at least 2 rows, by the number of columns
-- you are going to implement uniqueness on
INSERT INTO MyNumbersTable
SELECT 1 UNION ALL
SELECT 2;
GO
CREATE TABLE MyUniqueCities (  -- the main table
  ID int IDENTITY,
  City1 varchar(50) NOT NULL,
  City2 varchar(50) NOT NULL
);
GO
CREATE VIEW MyIndexedView
WITH SCHEMABINDING  -- this is required for creating an indexed view
AS
SELECT
  City = CASE t.Value    -- after supplying the numbers table
    WHEN 1 THEN u.City1  -- with the necessary number of rows
    WHEN 2 THEN u.City2  -- you can extend this CASE expression
  END                    -- to add more columns to the constraint
FROM dbo.MyUniqueCities u
  INNER JOIN dbo.MyNumbersTable t
    ON t.Value BETWEEN 1 AND 2  -- change here too for more columns
GO
-- the first index on an indexed view *must* be unique,
-- which suits us perfectly
CREATE UNIQUE CLUSTERED INDEX UIX_MyIndexedView ON MyIndexedView (City)
GO
-- the first two rows insert fine
INSERT INTO MyUniqueCities VALUES (\'London\', \'New York\');
INSERT INTO MyUniqueCities VALUES (\'Amsterdam\', \'Prague\');
-- the following insert produces an error, because of \'London\'
INSERT INTO MyUniqueCities VALUES (\'Melbourne\', \'London\');
GO
DROP VIEW MyIndexedView
DROP TABLE MyUniqueCities
DROP TABLE MyNumbersTable
GO