HTMLAgilityPack仅迭代所有文本节点
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这是一个HTML代码段，我只想获取文本节点并对其进行迭代。请让我知道。谢谢。
<div>
<div>
Select your Age:
<select>
<option>0 to 10</option>
<option>20 and above</option>
</select>
</div>
<div>
Help/Hints:
<ul>
<li>This is required field.
<li>Make sure select the right age.
</ul>
<a href=\"#\">Learn More</a>
</div>
</div>
没有找到相关结果
已邀请:
2 个回复
浮凰量
HtmlDocument doc = new HtmlDocument(); doc.Load(yourHtmlFile); foreach (HtmlNode node in doc.DocumentNode.SelectNodes(\"//text()[normalize-space(.) != \'\']\")) { Console.WriteLine(node.InnerText.Trim()); }摊揉售
public string getBodyText(string html) { string str = \"\"; HtmlAgilityPack.HtmlDocument doc = new HtmlAgilityPack.HtmlDocument(); doc.LoadHtml(html); try { // Remove script & style nodes doc.DocumentNode.Descendants().Where( n => n.Name == \"script\" || n.Name == \"style\" ).ToList().ForEach(n => n.Remove()); // Simon Mourier\'s Answer foreach (HtmlNode node in doc.DocumentNode.SelectNodes(\"//text()[normalize-space(.) != \'\']\")) { str += node.InnerText.Trim() + \" \"; } } catch (Exception) { } return str; }