Symfony管理员生成器，链接到过滤结果
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我有以下模型的管理员生成器：
#schema.yml
Author:
columns:
name: { type: string(255), notnull: true }
Book:
columns:
authorId: { type: integer, notnull: true }
title: { type: string(512), notnull: true }
content: { type: string(512), notnull: true }
relations:
Author: { onDelete: CASCADE, local: authorId, foreign: id, foreignAlias: Books}
php symfony doctrine:generate-admin backend Author
php symfony doctrine:generate-admin backend Book
#generator.yml for Author
# ...
config:
actions: ~
fields:
list:
display: [id, name, _booksLink]
filter: ~
form: ~
edit: ~
new: ~
<!-- modules/author/templates/_booksLink.php -->
<a href=\"<?= link_to(\'book?author_id=\'.$author->getId()) ?>\"><!-- how to select filter? -->
See <?= $author->getName() ?> books
</a>
没有找到相关结果
已邀请:
1 个回复
硕歌沙
class AuthorActions extends AutoAuthorActions { public function executeViewBooks($request) { $this->getUser()->setAttribute( \'book.filters\', array(\'authorId\' => $request->getParameter(\'id\')), \'admin_module\' ); $this->redirect($this->generateUrl(\'book\')); } }，则必须在上面的函数（第5行）中写入。如果架构中有“ 7”，则必须在函数中编写“ 7”。另外，模块名称总是带小写的下划线（例如：）。 在您的generator.yml中list: object_actions: _edit: ~ _delete: ~ viewPhones: { label: View books, action: viewBooks }