Python3-解析jpeg尺寸信息
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我正在尝试编写python函数来解析jpeg文件中的宽度和高度。我目前拥有的代码如下所示
import struct
image = open(\'images/image.jpg\',\'rb\')
image.seek(199)
#reverse hex to deal with endianness...
hex = image.read(2)[::-1]+image.read(2)[::-1]
print(struct.unpack(\'HH\',hex))
image.close()
没有找到相关结果
已邀请:
3 个回复
容淑阔九
jpeg.read(2) b = jpeg.read(1) try: while (b and ord(b) != 0xDA): while (ord(b) != 0xFF): b = jpeg.read(1) while (ord(b) == 0xFF): b = jpeg.read(1) if (ord(b) >= 0xC0 and ord(b) <= 0xC3): jpeg.read(3) h, w = struct.unpack(\">HH\", jpeg.read(4)) break else: jpeg.read(int(struct.unpack(\">H\", jpeg.read(2))[0])-2) b = jpeg.read(1) width = int(w) height = int(h) except struct.error: pass except ValueError: pass戊袱
import struct import io height = -1 width = -1 dafile = open(\'test.jpg\', \'rb\') jpeg = io.BytesIO(dafile.read()) try: type_check = jpeg.read(2) if type_check != b\'\\xff\\xd8\': print(\"Not a JPG\") else: byte = jpeg.read(1) while byte != b\"\": while byte != b\'\\xff\': byte = jpeg.read(1) while byte == b\'\\xff\': byte = jpeg.read(1) if (byte >= b\'\\xC0\' and byte <= b\'\\xC3\'): jpeg.read(3) h, w = struct.unpack(\'>HH\', jpeg.read(4)) break else: jpeg.read(int(struct.unpack(\">H\", jpeg.read(2))[0])-2) byte = jpeg.read(1) width = int(w) height = int(h) print(\"Width: %s, Height: %s\" % (width, height)) finally: jpeg.close()烷刨画颠离
否则，请使用Hachoir，它是一个纯Python库；特别是hachoir-metadata似乎具有您想要的功能）。