分号在Coq中的奇怪行为
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我在理解为什么我的Coq代码没有达到我期望的以下代码时遇到问题。
我试图使该示例尽可能简化，但是当我使它变得更加简单时，该问题就不再出现。
它使用的是CompCert 1.8文件。
这在Coq 8.2-pl2下发生在我身上。
这是代码：
Require Import Axioms.
Require Import Coqlib.
Require Import Integers.
Require Import Values.
Require Import Asm.
Definition foo (ofs: int) (c: code) : Prop :=
c <> nil /\\ ofs <> Int.zero.
Inductive some_prop: nat -> Prop :=
| some_prop_ctor :
forall n other_n ofs c lo hi ofs_ra ofs_link,
some_prop n ->
foo ofs c ->
find_instr (Int.unsigned ofs) c <> Some (Pallocframe lo hi ofs_ra ofs_link) ->
find_instr (Int.unsigned ofs) c <> Some (Pfreeframe lo hi ofs_ra ofs_link) ->
some_prop other_n
.
Lemma simplified:
forall n other_n ofs c,
some_prop n ->
foo ofs c ->
find_instr (Int.unsigned ofs) c = Some Pret ->
some_prop other_n.
Proof.
intros.
eapply some_prop_ctor
with (lo:=0) (hi:=0) (ofs_ra:=Int.zero) (ofs_link:=Int.zero);
eauto; rewrite H1; discriminate.
rewrite H1
Error:
Found no subterm matching \"find_instr (Int.unsigned ofs) c\" in the current goal.
eapply some_prop_ctor
with (lo:=0) (hi:=0) (ofs_ra:=Int.zero) (ofs_link:=Int.zero);
eauto.
rewrite H1; discriminate.
rewrite H1; discriminate.
Qed.
2 subgoals
n : nat
other_n : nat
ofs : int
c : code
H : some_prop n
H0 : foo ofs c
H1 : find_instr (Int.unsigned ofs) c = Some Pret
______________________________________(1/2)
find_instr (Int.unsigned ofs) c <> Some (Pallocframe 0 0 Int.zero Int.zero)
______________________________________(2/2)
find_instr (Int.unsigned ofs) c <> Some (Pfreeframe 0 0 Int.zero Int.zero)
rewrite H1; discriminate
eauto
Require Import Axioms.
Require Import Coqlib.
Require Import Integers.
Require Import Values.
Require Import Asm.
Definition foo (ofs: int) (c: code) : Prop :=
c <> nil /\\ ofs <> Int.zero.
Inductive some_prop: nat -> Prop :=
| some_prop_ctor :
forall n other_n ofs c lo hi ofs_ra ofs_link,
some_prop n ->
foo ofs c ->
find_instr (Int.unsigned ofs) c <> Some (Pallocframe lo hi ofs_ra ofs_link) ->
find_instr (Int.unsigned ofs) c <> Some (Pfreeframe lo hi ofs_ra ofs_link) ->
some_prop other_n
.
Lemma simplified:
forall n other_n ofs c,
some_prop n ->
foo ofs c ->
find_instr (Int.unsigned ofs) c = Some Pret ->
some_prop other_n.
Proof.
intros.
(*** This does not work:
eapply some_prop_ctor
with (lo:=0) (hi:=0) (ofs_ra:=Int.zero) (ofs_link:=Int.zero);
eauto; rewrite H1; discriminate.
***)
eapply some_prop_ctor
with (lo:=0) (hi:=0) (ofs_ra:=Int.zero) (ofs_link:=Int.zero);
eauto.
rewrite H1; discriminate.
rewrite H1; discriminate.
Qed.
没有找到相关结果
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1 个回复
冉案
是可以的。在这种情况下，“ 14”将迫使存在变量统一，从而释放重写的能力。