排列宝石
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我正在尝试获取一个字符串列表，这些字符串是字母，数字和破折号的组合，长度从1到63不等。
我正在使用置换宝石，并尝试使用
join(\'\')
length = 1
alphabet = [(\'a\'..\'z\').to_a, (\'0\'..\'9\').to_a, (\'-\').to_a].flatten
while length < 64
puts (alphabet.permutation(length){|x| p x}).join(\'\')
length += 1
end
[\"r\", \"q\", \"l\"]
[\"r\", \"q\", \"m\"]
没有找到相关结果
已邀请:
2 个回复
博沮富教全
[\'a\',\'b\',\'c\'].permutation(3).collect { |x| x.join(\'\')}感秆暴壳
query = \"Jo Svenda Schmidt\".split => [\"Jo\", \"Svenda\", \"Schmidt\"] query.permutation(query.length).collect { |x| x.join(\" AND \") }.join(\" OR \") => \"Jo AND Svenda AND Schmidt OR Jo AND Schmidt AND Svenda OR Svenda AND Jo AND Schmidt OR Svenda AND Schmidt AND Jo OR Schmidt AND Jo AND Svenda OR Schmidt AND Svenda AND Jo\"