NSObject和NSMutableArray问题
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您好,我有这个NS对象:
@interface Checkin : NSObject {
NSString *name;
NSString *profID;
NSString *time;
NSString *lon;
NSString *lat;
NSString *country;
NSString *city;
NSString *place;
NSString *photoURL;
NSMutableArray *taggedID;
NSMutableArray *taggedName;
}
@property(nonatomic, retain)NSString *name;
@property(nonatomic, retain)NSString *profID;
@property(nonatomic, retain)NSString *time;
@property(nonatomic, retain)NSString *lon;
@property(nonatomic, retain)NSString *lat;
@property(nonatomic, retain)NSString *country;
@property(nonatomic, retain)NSString *city;
@property(nonatomic, retain)NSString *place;
@property(nonatomic, retain)NSString *photoURL;
@property(nonatomic, retain)NSMutableArray *taggedID;
@property(nonatomic, retain)NSMutableArray *taggedName;
@end
现在,我想创建一个NSMutable数组,并在其中添加几个\“ Checkins \”。
当我这样做时:
Checkin *checkinsA = [[NSObject alloc] init];
NSDictionary *decodedJson = result;
NSArray *users = [decodedJson objectForKey:@\"data\"];
for(NSDictionary *user in users) {
NSLog(@\"Created item: %@ \\n\", [user objectForKey:@\"created_time\"]);
checkinsA.time = [NSString stringWithFormat:@\"%@\",[user objectForKey:@\"created_time\"]];
NSDictionary *fromData = [user objectForKey:@\"from\"];
NSLog(@\"user id is: %@ \\n\", [fromData objectForKey:@\"id\"]);
checkinsA.profID = [fromData objectForKey:@\"id\"];
NSLog(@\"user name is: %@\\n \", [fromData objectForKey:@\"name\"]);
checkinsA.name =[fromData objectForKey:@\"name\"];
NSDictionary *placeData = [user objectForKey:@\"place\"];
NSDictionary *locationData = [placeData objectForKey:@\"location\"];
NSLog(@\"City: %@ \\n\", [locationData objectForKey:@\"city\"]);
checkinsA.city = [locationData objectForKey:@\"city\"];
NSLog(@\"Country: %@ \\n\", [locationData objectForKey:@\"country\"]);
checkinsA.country = [locationData objectForKey:@\"country\"];
NSLog(@\"Latitude: %@ \\n\", [locationData objectForKey:@\"latitude\"]);
checkinsA.lat = [locationData objectForKey:@\"latitude\"];
NSLog(@\"Longitude: %@ \\n\", [locationData objectForKey:@\"longitude\"]);
checkinsA.lon = [locationData objectForKey:@\"longitude\"];
NSLog(@\"Place name: %@ \\n\", [placeData objectForKey:@\"name\"]);
checkinsA.place = [placeData objectForKey:@\"name\"];
NSDictionary *tagData = [user objectForKey:@\"tags\"];
NSArray *tagDataArray = [tagData objectForKey:@\"data\"];
for(NSDictionary *tagData2 in tagDataArray){
NSLog(@\"tagged user id is: %@ \\n\", [tagData2 objectForKey:@\"id\"]);
[checkinsA.taggedID addObject:[tagData2 objectForKey:@\"id\"]];
NSLog(@\"tagged user name is: %@\\n \", [tagData2 objectForKey:@\"name\"]);
[checkinsA.taggedName addObject:[tagData2 objectForKey:@\"name\"]];
}
[checkinArray addObject:checkinsA];
}
我收到错误消息:
-[NSObject setTime:]:无法识别的选择器已发送到的实例
checkinsA.time = [NSString stringWithFormat:@ \“%@ \”,[user objectForKey:@ \“ created_time \”]]];
更改checkinsA.time checkins.id等值的正确方法是什么?
没有找到相关结果
已邀请:
1 个回复
梆晨灸碾
不是
对象,而是一个ѭ4si(因为这是您分配的对象),而
没有
方法。尝试以下方法: