提取文本/ XML文件时，Dotnetzip错误状态错误
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我正在尝试通过以下方法使用dotnetzip将XML文件存储到zip中：
private void writeHosts()
{
XmlRootAttribute root = new XmlRootAttribute(ROOTNAME_HOST);
XmlSerializer ser = new XmlSerializer(typeof(Host[]), root);
MemoryStream ms = new MemoryStream();
StreamWriter swriter = new StreamWriter(ms);
//write xml to memory stream
ser.Serialize(swriter, m_hostList.ToArray());
swriter.Flush();
//be kind, rewind (the stream)
ms.Seek(0, SeekOrigin.Begin);
//copy memory stream to zip as a file.
using (m_repo)
{
ZipEntry e = m_repo.AddEntry(FILENAME_HOST, ms);
e.IsText = true;
m_repo.Save();
}
swriter.Close();
}
private List<Host> readHosts()
{
XmlRootAttribute root = new XmlRootAttribute(ROOTNAME_HOST);
XmlSerializer ser = new XmlSerializer(typeof(Host[]), root);
MemoryStream ms = new MemoryStream();
StreamReader reader = new StreamReader(ms);
List<Host> retlist = new List<Host>();
//get the vuln list from the zip and read into memory
using (m_repo)
{
ZipEntry e = m_repo[FILENAME_HOST];
e.Extract(ms);
}
//rewind to the start of the stream
ms.Flush();
ms.Seek(0, SeekOrigin.Begin);
//Pull the host list from XML
Host[] ret = (Host[])ser.Deserialize(reader);
retlist.AddRange(ret);
ms.Close();
return retlist;
}
没有找到相关结果
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攫怂绵十
public class Scrilla { // the parts that get serialized: [XmlElement] public String Name { get;set; } [XmlElement] public DateTime FirstReport { get;set; } [XmlElement] public String MoreInfo { get;set; } }var FILENAME_HOST = \"self.xml\"; XmlRootAttribute root = new XmlRootAttribute(\"root\"); XmlSerializer ser = new XmlSerializer(typeof(Scrilla), root); MemoryStream zipStream = new MemoryStream(); var scrilla = new Scrilla { Name = \"Foop\", FirstReport = DateTime.Now, MoreInfo = \"see http://example.org\" }; // zip up: using (var zip1 = new ZipFile()) { zip1.AddEntry(FILENAME_HOST,(entryName,stream) => { using (var swriter = new StreamWriter(stream)) { ser.Serialize(swriter, scrilla); }}); zip1.Save(zipStream); } // the content (an XML file) is now held in the MemoryStream zipStream.Seek(0, SeekOrigin.Begin);Scrilla unpacked; // unzip: using (var zip2 = ZipFile.Read(zipStream)) { Stream s = zip2[FILENAME_HOST].OpenReader(); unpacked = (Scrilla) ser.Deserialize(new StreamReader(s)); }// prove that it worked - print out to Console var xmlws = new System.Xml.XmlWriterSettings { OmitXmlDeclaration = true, Indent= true }; using ( var w2 = System.Xml.XmlWriter.Create(Console.Out, xmlws)) { ser.Serialize(w2, unpacked); }