需要帮助找到正确的T-SQL查询

| 我不太确定该怎么做。基本上我有这样的桌子
UserId       DateRequested           Approved ApprovedBy  Notes
------------ ----------------------- -------- ----------- -----
1            2011-05-26               0        NULL        NULL
1            2011-05-27               0        NULL        NULL
1            2011-05-28               0        NULL        NULL
1            2011-06-05               0        NULL        NULL
1            2011-06-06               0        NULL        NULL
1            2011-06-25               0        NULL        NULL
它主要包含员工要求放假的日子。现在,当授予一天或几天后,需要将这些数据复制到表格的表格中
UserId DateFrom DateTo
所以基本上对于我想要的上述数据:
UserId DateFrom DateTo 
-------------------------------
1      2011-05-26 2011-05-28 
1      2011-06-05 2011-06-06 
1      2011-06-25 2011-06-25 
即我想在DateFrom和DateTo中连续几天。现在,我不确定在不使用while循环的情况下如何执行此操作。这是SQL,所以我宁愿使用非迭代解决方案。 请指教!!!     
已邀请:
;WITH cte AS
(
SELECT *,
        DATEDIFF(DAY,0,DateRequested)-
        ROW_NUMBER() OVER (PARTITION BY UserId ORDER BY DateRequested) AS Grp
FROM YourTable  
WHERE Approved = 1 /*Presumably - but your example data doesn\'t show this.*/
)
SELECT UserId, 
       MIN(DateRequested) AS DateFrom, 
       MAX(DateRequested) AS DateTo  
FROM cte 
GROUP BY UserId,Grp
    
在Oracle PL / SQL中,其编写方式如下:
WITH cte
        AS (SELECT a.*,
                   daterequested - TRUNC (SYSDATE)
                   - ROW_NUMBER ()
                        OVER (PARTITION BY UserId ORDER BY DateRequested)
                      AS Grp
              FROM yourtable a
             WHERE Approved = 0)
  SELECT UserId, MIN (DateRequested) AS DateFrom, MAX (DateRequested) AS DateTo
    FROM cte
GROUP BY UserId, Grp;
    

要回复问题请先登录注册