如何从嵌套模型中引用高级模型？
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我正在尝试根据付款模型中的项目状态进行条件验证。例如，状态可以是\“ Talks \”或\“ Active \”。考虑以下结构，最好的方法是什么？
class Project < ActiveRecord::Base
has_many :costs, :dependent => :destroy
has_many :payments, :through => :costs, :dependent => :destroy
accepts_nested_attributes_for :costs, :allow_destroy => true
end
class Cost < ActiveRecord::Base
has_many :payments, :dependent => :destroy
accepts_nested_attributes_for :payments, :allow_destroy => true
belongs_to :project
end
class Payment < ActiveRecord::Base
belongs_to :cost
validates_presence_of :value1, :if => :new?
validates_presence_of :value1, :if => :talks?
validates_presence_of :value2, :if => :active?
def new?
# if controller action is new
end
def talks?
# if project status is \"Talks\" (edit action)
end
def active?
# if project status is \"Active\" (edit action)
end
end
没有找到相关结果
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1 个回复
仿普
class Payment < ActiveRecord::Base belongs_to :cost has_one :project, :through => :cost validates_presence_of :value1, :if => :new? validates_presence_of :value1, :if => :talks? validates_presence_of :value2, :if => :active? def new? self.new_record? end def talks? project.status == \"talks\" end def active? project.status == \"active\" end end