在运行时对向量执行C ++断言失败表达式:向量下标超出范围

|| 即时消息这真烦人的错误消息。我知道我对此并不陌生,但似乎可以弄清楚。谁能告诉我我哪里出问题了? 运行时的消息是: 调试断言失败! 程序: .... 文件:c:\\ program files \\ Microsoft Visual Studio 10.0 \\ vc \\ include \\ vector 线:932 表达式:向量下标超出范围 和代码是
#include \"VectorIntStorage.h\"
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <algorithm>

using namespace std;

void VectorIntStorage::Read(istream& r)
{
    char c[13];
    r >> c;
    r >> NumberOfInts; //gets number of ints for vector

    //numberVector = new std::vector<int> numberVector;

    for(int i = 0; i < NumberOfInts; i++)
    {
        r >> numberVector[i];
        cout << numberVector[i] << endl;

        if(_sortRead) //true
        {
            for(int k = 0; k < i; k++)
            {
                if(numberVector[i] < numberVector[k])
                {
                    int temp = numberVector[k];
                    numberVector[k] = numberVector[i];
                    numberVector[i] = temp;
                }
            }
        }
    }
}

void VectorIntStorage::Write(ostream& w)
{
    for(int i = 0; i < NumberOfInts; i++)
    {
        w << numberVector[i] << endl;
        cout << numberVector[i] << endl;
    }
}

void VectorIntStorage::sortStd()
{
    sort(numberVector.begin(), numberVector.end());
}

void VectorIntStorage::sortOwn()
{
    quickSort(0, NumberOfInts - 1);
}

void VectorIntStorage::setReadSort(bool sort)
{
    _sortRead = sort;
}

void VectorIntStorage::quickSort(int left, int right)
{
     int i = left, j = right;
      int tmp;
      int pivot = numberVector[(left + right) / 2];

      while (i <= j)
      {
            while (numberVector[i] < pivot)
                  i++;
            while (numberVector[j] > pivot)
                  j--;
            if (i <= j) 
            {
                  tmp = numberVector[i];
                  numberVector[i] = numberVector[j];
                  numberVector[j] = tmp;
                  i++;
                  j--;
            }
      }

      if (left < j)
      {
            quickSort(left, j);
      }
      if (i < right)
      {
            quickSort(i, right);
      }
}

VectorIntStorage::VectorIntStorage(const VectorIntStorage& copying)
{
    //int *duplicate = new int[(copying.NumberOfInts)];
    //vector<int> *duplicate = new vector<int>;

    //std::copy(numberVector.begin(), numberVector.end(), duplicate);
    //numberVector = duplicate;
    //NumberOfInts = copying.NumberOfInts;
}

VectorIntStorage::VectorIntStorage(void)
{
}


VectorIntStorage::~VectorIntStorage(void)
{
}
    
已邀请:
我们没有足够的信息可以肯定地说,但我怀疑失败的行是
r >> numberVector[i]
。我想你想说
int j; r >> j; numberVector.push_back(j);
问题恰恰是错误消息说的是:您的向量下标(
i
)超出范围。具体来说,您永远不会增加向量的大小,因此向量的大小始终为0。因此,对
operator[]
的任何使用都将引用超出范围的元素。     
您不能不先呼叫
numberVector.resize()
就使用
numberVector[i]
vector<int> vec;
vec[1] = 0; // fails - vec is empty so [1] is out of range
vec.resize(100);
vec[1] = 5; // ok, you can access vec[0] .. vec[99] now
vec.push_back(11); // Now the size is 101 elements, you can access vec[0] .. vec[100]
    
r >> NumberOfInts; //gets number of ints for vector
从以上评论看来,您需要一个大小为
NumberOfInts
的向量。但是,请保留注释行-
//numberVector = new std::vector<int> numberVector;
您将向量声明为-
std::vector<int> numberVector; // The size of the vector is 0
要在
numberVector
上执行
[]
的操作,在声明时应提及其大小,并且大小应在有效范围内。由于声明时未提及,因此您需要执行
push_back
操作来动态增加向量的大小。
for(int i = 0; i < NumberOfInts; i++)
{
    r >> numberVector[i];    // Size isnot initially mentioned while declaration 
                             // of the vector to do an `[]` operation
    cout << numberVector[i] << endl;
    // ....
    

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