Boost Fusion / MPL：将类型从序列转换为等效any_range的序列
我想使用Boost的
any_range
typedef vector<double, int, char> TypeSequence
vector<AnyRange<double>::value, AnyRange<int>::value, AnyRange<char>::value>
AnyRange
using namespace boost;
template <typename T>
struct AnyRange
{
typedef typename any_range<typename T, forward_pass_traversal_tag, int, std::ptrdiff_t> value;
};
any_range
没有找到相关结果
已邀请:
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貉骂
#include <boost/range/any_range.hpp> #include <boost/fusion/include/mpl.hpp> // Required to adapt Fusion to MPL #include <boost/fusion/include/vector.hpp> #include <boost/mpl/transform.hpp> template < typename T > struct EmbedInAnyRange { typedef boost::any_range< // no need for typename here T, // no need for typename here forward_pass_traversal_tag, int, // not sure what this parameter is, I leave int... std::ptrdiff_t > type; }; int main() { typedef boost::fusion::vector< double, int, char > Tuple; typedef boost::mpl::transform< Tuple, EmbedInAnyRange< boost::mpl::_ > >::type AnyRangeTuple; AnyRangeTuple myTuple( std::vector< double >(), std::list< int >(), std::vector< char >() ); }template < typename Seq > struct EmbedAllInAnyRange { typedef typename boost::mpl::transform< // typename needed Seq, EmbedInAnyRange< boost::mpl::_ > >::type type; }; ... typedef EmbedAllInRange< Tuple >::type AnyRangeTuple;