这是一个理智的Objective-C Block实现吗？
我想要一个NSRegularExpression的variation0ѭ方法的变体，它采用块而不是模板。块的返回值将用作替换值。您可以想象，这比模板更灵活。有点像在Perl正则表达式中使用
/e
@implementation NSRegularExpression (Block)
- (NSString *)stringByReplacingMatchesInString:(NSString *)string
options:(NSMatchingOptions)options
range:(NSRange)range
usingBlock:(NSString* (^)(NSTextCheckingResult *result))block
{
NSMutableString *ret = [NSMutableString string];
NSUInteger pos = 0;
for (NSTextCheckingResult *res in [self matchesInString:string options:options range:range]) {
if (res.range.location > pos) {
[ret appendString:[string substringWithRange:NSMakeRange(pos, res.range.location - pos)]];
}
pos = res.range.location + res.range.length;
[ret appendString:block(res)];
}
if (string.length > pos) {
[ret appendString:[string substringFromIndex:pos]];
}
return ret;
}
@end
-enumerateMatchesInString:options:range:usingBlock:
pos
@implementation NSRegularExpression (Block)
- (NSString *)stringByReplacingMatchesInString:(NSString *)string
options:(NSMatchingOptions)options
range:(NSRange)range
usingBlock:(NSString * (^)(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop))block
{
NSMutableString *ret = [NSMutableString string];
__block NSUInteger pos = 0;
[self enumerateMatchesInString:string options:options range:range usingBlock:^(NSTextCheckingResult *match, NSMatchingFlags flags, BOOL *stop)
{
if (match.range.location > pos) {
[ret appendString:[string substringWithRange:NSMakeRange(pos, match.range.location - pos)]];
}
pos = match.range.location + match.range.length;
[ret appendString:block(match, flags, stop)];
}];
if (string.length > pos) {
[ret appendString:[string substringFromIndex:pos]];
}
return [NSString stringWithString:ret];
}
@end
没有找到相关结果
已邀请:
1 个回复
鞋扣蚊冈借
就像更改声明一样简单：至：关于关键字的更多信息：变量