c#pad left to string

我想找到一个有效的方法: 我有一个像这样的字符串:
'1,2,5,11,33'
我想仅将零填充到低于10的数字(有一位数) 所以我想要
'01,02,05,11,33'
谢谢     
已邀请:
你真的关心效率多少钱?就个人而言我会用:
string padded = string.Join(",", original.Split(',')
                                         .Select(x => x.PadLeft(2, '0')));
(正如评论中所指出的,如果你使用.NET 3.5,你需要在
Select
之后拨打
ToArray
。) 这绝对不是最有效的解决方案,但在我证明它不够有效之前,我会使用它。这是另一种选择......
// Make more general if you want, with parameters for the separator, length etc
public static string PadCommaSeparated(string text)
{
    StringBuilder builder = new StringBuilder();
    int start = 0;
    int nextComma = text.IndexOf(',');
    while (nextComma >= 0)
    {
        int itemLength = nextComma - start;
        switch (itemLength)
        {
            case 0:
                builder.Append("00,");
                break;
            case 1:
                builder.Append("0");
                goto default;
            default:
                builder.Append(text, start, itemLength);
                builder.Append(",");
                break;
        }
        start = nextComma + 1;
        nextComma = text.IndexOf(',', start);
    }
    // Now deal with the end...
    int finalItemLength = text.Length - start;
    switch (finalItemLength)
    {
        case 0:
            builder.Append("00");
            break;
        case 1:
            builder.Append("0");
            goto default;
        default:
            builder.Append(text, start, finalItemLength);
            break;
    }
    return builder.ToString();
}
这是可怕的代码,但我认为它会做你想要的......     
string input= "1,2,3,11,33";
string[] split = string.Split(input);
List<string> outputList = new List<string>();
foreach(var s in split)
{
    outputList.Add(s.PadLeft(2, '0'));
}

string output = string.Join(outputList.ToArray(), ',');
    

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