在Java中将整数数组转换为字符串的最佳方法
在Java中，我有一个整数数组。有没有快速的方法将它们转换为字符串？
I.E.
int[] x = new int[] {3,4,5}没有找到相关结果
已邀请:
7 个回复
翁茄口霉氖
StringBuilder builder = new StringBuilder(); for (int i : array) { builder.append(i); } String text = builder.toString();类 - 虽然我不相信你能用它来做原始数组。编辑：如下所述，你可以使用。雇砰
int[] x = new int[] {3,4,5}; String s = java.util.Arrays.toString(x).replaceAll("[\,\[\]\ ]", "")String s = IntStream.of(x) .mapToObj(Integer::toString) .collect(Collectors.joining(""));艰管垮淮
StringBuffer str =new StringBuffer(); for(int i:x){ str.append(i); }马口
然后 -String temp = Arrays.toString( intArray ).replace(", ", ""); String finalStr = temp.substring(1, temp.length()-2);穗揣
public static void main(String[] args) { int[] dice = {1, 2, 3, 4, 5, 0}; String string = ""; for (int i = 0; i < dice.length; i++) { string = string + dice[i]; } System.out.print(string); }慰泥悍瓶
public static void main(String[] args) { System.out.println("Integer Value :" +convertIntToString(new int[]{3,4,5})); } public static String convertIntToString(int intArray[]) { List<Integer> listInteger = new ArrayList<Integer>(); for (int i = 0; i < intArray.length; i++) { listInteger.add(intArray[i]); } Object o = listInteger; return String.valueOf(o).replace("[", "").trim().replaceAll(", ","").trim().replaceAll("\]","").trim(); }席酱
public static void main(String[] args) { System.out.println("Integer Value :" +convertIntToString(new int[]{3,4,5})); } public static String convertIntToString(int intArray[]) { List<Integer> listInteger = new ArrayList<Integer>(); for (int i = 0; i < intArray.length; i++) { listInteger.add(intArray[i]); } Object o = listInteger; return String.valueOf(o).replace("[", "").trim().replaceAll(", ","").trim().replaceAll("\]","").trim(); }