第二个MySQL查询不起作用
检查此代码：
$select = mysql_query("SELECT * FROM nieuws ORDER BY id DESC LIMIT 1");
while($row = mysql_fetch_assoc($select)) {
$datum = $row['time'];
$titel = $row['title'];
$bericht = $row['message'];
?>
<div class="entry">
<span class="blue date"><?php echo "$datum"; ?></span>
<h3><?php echo "$titel"; ?></h3>
<p><?php echo "$bericht"; ?></p> <br />
</div><!-- end of entry --> <?php } ?>
<?php
$select2 = mysql_query("SELECT * FROM nieuws ORDER BY id DESC LIMI 1, 1");
while($row2 = mysql_fetch_assoc($select2)) {
$datum = $row2['time'];
$titel = $row2['title'];
$bericht = $row2['message'];
?>
<div class="entry">
<span class="green date"><?php echo "$datum"; ?> </span>
<h3><?php echo "$titel"; ?></h3>
<p><?php echo "$bericht"; ?></p>
</div> <!-- end of entry --> <?php } ?>
</div><!-- end of news -->
没有找到相关结果
已邀请:
4 个回复
超可林
应该凄挡
秃拳割
$select2 = mysql_query("SELECT * FROM nieuws ORDER BY id DESC LIMI 1, 1");购藏盗码韦
if( !$select2 ) { echo mysql_error(); }