MySQL视图中的BLOB而不是正确的数据

我使用两个表中的
UNION ALL
创建了一个MySQL视图,这样我就可以在这些表中获得相同数据的相同列名(即
tbl1.author2 AS translator
...
tbl2.translator AS translator
)等等,问题是当我尝试从该视图中选择一些东西时,一半的数据是
BLOB
,而不是原始值。 视图定义是:
SELECT e.id AS prod_id, 
e.price_vat AS price_vat, 
e.product AS title, 
e.authors AS author, 
e.isbn AS isbn, 
e.ean AS ean, 
e.page_count AS page_count, 
e.publishers AS publishers, 
e.issue_year AS issue_year,
'e' AS type
FROM ama_euromedia_products AS e
UNION ALL
SELECT
k.publishers AS publishers, 
DATE_FORMAT(k.publication_date, '%Y') AS issue_year,
k.ean AS ean, 
k.number_of_pages AS page_count, 
k.author AS author, 
k.isbn AS isbn, 
k.title_full AS title, 
k.price_amount AS price_vat, 
k.internal AS prod_id,
'k' AS type
FROM ama_kosmas_products AS k 
表定义:
CREATE TABLE `ama_euromedia_products` (
  `id` int(9) NOT NULL,
  `product` text COLLATE utf8_czech_ci NOT NULL,
  `isbn` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `authors` text COLLATE utf8_czech_ci,
  `publishers` text COLLATE utf8_czech_ci,
  `price` float(9,0) DEFAULT NULL,
  `price_vat` float(9,0) DEFAULT NULL,
  `vat` int(3) DEFAULT NULL,
  `availability` tinyint(1) DEFAULT NULL,
  `genres` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `ean` bigint(14) DEFAULT NULL,
  `page_count` int(7) DEFAULT NULL,
  `issue_year` int(4) DEFAULT NULL,
  `supply_date` timestamp NULL DEFAULT NULL,
  `width` int(7) DEFAULT NULL,
  `height` int(7) DEFAULT NULL,
  `weight` int(7) DEFAULT NULL,
  `binding` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `long_v` text COLLATE utf8_czech_ci,
  `short` text COLLATE utf8_czech_ci,
  `imgurl` text COLLATE utf8_czech_ci,
  `is_preliminary` tinyint(1) DEFAULT NULL,
  `stack_date` timestamp NULL DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP,
  `invoice_only` tinyint(1) DEFAULT NULL,
  `new` tinyint(1) DEFAULT NULL,
  `sale` tinyint(1) DEFAULT NULL,
  `return_v` tinyint(1) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `indexy` (`id`,`isbn`,`genres`,`ean`,`issue_year`,`supply_date`,`stack_date`,`new`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_czech_ci;


CREATE TABLE `ama_kosmas_products` (
  `id` int(7) NOT NULL AUTO_INCREMENT,
  `internal` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `isbn` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `ean` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `contained_items` text COLLATE utf8_czech_ci,
  `title_original` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `title_full` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `subtitle` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `other_text` text COLLATE utf8_czech_ci,
  `languages` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `author` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `illustrator` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `translator` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `number_of_pages` int(7) DEFAULT NULL,
  `subject_scheme_name` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `subject_code` int(7) DEFAULT NULL,
  `subject_heading_text` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `media_file_label` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `media_file_thumbnail` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
  `publishers` text COLLATE utf8_czech_ci,
  `publishing_status` tinyint(2) DEFAULT NULL,
  `publication_date` timestamp NULL DEFAULT NULL,
  `product_availability` tinyint(2) DEFAULT NULL,
  `on_hand` int(7) DEFAULT NULL,
  `on_order` int(7) DEFAULT NULL,
  `price_amount` int(7) DEFAULT NULL,
  `price_tax_rate_code` varchar(1) COLLATE utf8_czech_ci DEFAULT NULL,
  `price_tax_rate_percent` tinyint(2) DEFAULT NULL,
  `price_tax_amount` int(7) DEFAULT NULL,
  `price_taxable_amount` int(7) DEFAULT NULL,
  `reissue_date` timestamp NULL DEFAULT NULL,
  `invoice_only` tinyint(1) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `internal` (`internal`)
) ENGINE=MyISAM AUTO_INCREMENT=43341 DEFAULT CHARSET=utf8 COLLATE=utf8_czech_ci;
知道为什么会这样吗?     
已邀请:
使用
UNION
创建视图时,必须确保相应列的数据类型相同(或者至少足够相似,以便将其转换为另一列)。在当前情况下,视图的第一列是
publishers
price_vat
,除了
BLOB
之外没有任何数据类型定义可以很清楚。 如果你真的需要这个视图,你可以尝试......
SELECT e.price_vat AS price_vat, 
       NULL        AS publishers,
       ...etc...
       'e'         AS type
    FROM ama_euromedia_products AS e;
UNION ALL
SELECT
     NULL         AS price_vat,
     k.publishers AS publishers, 
     ...etc...
     'k'          AS type
     FROM ama_kosmas_products AS k;
在每列中获取单个数据类型。     

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