php if-statement语句针对列表，需要帮助以简化。
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因此，我试图为我为托管客户构建的一些基本站点构建一个小型的轻量级框架，并且尝试调用index.php中的各种include。
我已经弄清楚了，但是觉得必须有一种更好的方法来编写以下if语句：
<?php
if(\'home\'==$currentpage)
{
include(\'shared/footer.htm\');
}
elseif(\'testing\'==$currentpage)
{
include(\'shared/footer.htm\');
}
elseif(\'training\'==$currentpage)
{
include(\'shared/footer.htm\');
}
elseif(\'contact\'==$currentpage)
{
include(\'shared/footer.htm\');
}
elseif(\'pricing\'==$currentpage)
{
include(\'shared/footer.htm\');
}
?>
$arr = array(\'home\', \'testing\', \'training\', \'contact\');
foreach ($arr as &$value);
if ($value==$currentpage)
{
include(\'shared/footer.htm\');
}
没有找到相关结果
已邀请:
3 个回复
呸溉
$arr = array(\'home\', \'testing\', \'training\', \'contact\',\'pricing\'); if (in_array($currentpage,$arr)) { include(\'shared/footer.htm\'); }蔬谢窗港
$arrPage = array( \'home\' => \'shared/footer.htm\', \'testing\' => \'shared/footer.htm\', \'training\' => \'shared/footer.htm\', \'contact\' => \'shared/footer.htm\', \'pricing\' => \'shared/footer.htm\', ); if( array_key_exists( $arrPage, $currentPage )) include($arrPage[$currentpage]);犁攀富
$pages = array( \'home\' => \'shared/footer.htm\', \'testing\' => \'shared/footer.htm\', \'training\' => \'shared/footer.htm\' ); //and so forth if (isset($pages[$currentpage])) { include($pages[$currentpage]); } else { //show default page }