合并MySQL存储过程的结果
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我有一个存储过程，它基于用户可以选择要搜索的多个位置的事实来查找用户的首选项。因此，对于每个位置，查询都需要在该区域中查找结果。当前，该过程仅返回1个结果。另外，我希望能够实现某种排名系统，以便将结果作为一个合并的供稿进行排序。我意识到，如果我正在使用while循环，那么它将按位置对结果进行分组，而这并不是我想要的。重组此过程的最佳方法是什么，以便对3个查询的结果进行网格划分并使我可以灵活地对结果进行排序？
DELIMITER $$
DROP PROCEDURE IF EXISTS `geodist` $$
CREATE PROCEDURE geodist (IN userid INT) BEGIN
DECLARE mylon DOUBLE; DECLARE mylat DOUBLE;
DECLARE lon1 FLOAT; DECLARE lon2 FLOAT;
DECLARE lat1 FLOAT; DECLARE lat2 FLOAT;
DECLARE dist INT;
DECLARE no_more_locations INT; DECLARE l_location_count INT;
-- get the original lon and lat for the userid
DECLARE location_cursor CURSOR FOR
SELECT geo_lat, geo_long, distance
FROM activity_location_preferences
INNER JOIN activity_preferences ON activity_location_preferences.preference_id = activity_preferences.id
WHERE activity_preferences.user_id = userid
ORDER BY activity_preferences.id ASC
LIMIT 3;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET no_more_locations = 1;
SET no_more_locations = 0;
OPEN location_cursor;
location_loop:WHILE(no_more_locations = 0) DO
FETCH location_cursor INTO mylat, mylon, dist;
IF no_more_locations = 1 THEN
LEAVE location_loop;
END IF;
SET l_location_count = l_location_count+1;
-- calculate lon and lat for the rectangle:
SET lon1 = mylon - dist / abs(cos(radians(mylat)) * 69);
SET lon2 = mylon + dist / abs(cos(radians(mylat)) * 69);
SET lat1 = mylat - (dist / 69);
SET lat2 = mylat + (dist / 69);
-- run the query:
SELECT `id`, `user_id`, `activity`, `geo_lat`, `geo_long`, `data`, `date_created`,
7912 * ASIN(SQRT(POWER(SIN((mylat - activity_logs.geo_lat) * pi()/180 / 2), 2) +
COS(mylat * pi()/180) * COS(activity_logs.geo_lat * pi()/180) * POWER(SIN((mylon - activity_logs.geo_long) * pi()/180 / 2), 2) )) as distance
FROM activity_logs
WHERE 1
AND activity_logs.geo_long BETWEEN lon1 AND lon2
AND activity_logs.geo_lat BETWEEN lat1 AND lat2
HAVING distance < dist ORDER BY date_created DESC LIMIT 100;
END WHILE location_loop;
CLOSE location_cursor;
SET no_more_locations = 0;
END $$
DELIMITER ;
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