如何定义一个变量，我的对象中的所有函数都可以访问该变量？
|
我有一个这样的对象：
myobj={
//where to define Car car=new Car();
test:{
testFunc1(){car.paintTest();},
testFunc2(){car.drawTest();}
},
use:{
useFunc1(){car.paintUse();},
useFunc2(){car.drawUse();}
},
};
myobj
myobj.test.testFunc2();
myobj.use.useFunc1();
myobj
car
myobj
Car car=new Car();
car
myobj
没有找到相关结果
已邀请:
1 个回复
末钉蹈泰唬
myobj={ car: new Car(), test: { var self = this; testFunc1(){self.car.paintTest();}, testFunc2(){self.car.drawTest();} }, use: { var self = this; useFunc1(){self.car.paintUse();}, useFunc2(){self.car.drawUse();} }, };对象的工作版本：function Car (){ this.paintTest = function(){console.log(\'painttest\')} this.drawTest = function(){console.log(\'drawtest\')} this.paintUse = function(){console.log(\'paintuse\')} this.drawUse = function(){console.log(\'drawuse\')} } myobj = { car: new Car(), test:{ testFunc1: function() {myobj.car.paintTest();}, testFunc2: function() {myobj.car.drawTest();} }, use: { useFunc1: function(){myobj.car.paintUse();}, useFunc2: function(){myobj.car.drawUse();} }, }; myobj.test.testFunc1(); myobj.test.testFunc2(); myobj.use.useFunc1(); myobj.use.useFunc2();