类型为System.Xml.XmlElement的Powershell格式输出
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我正在尝试构建计算机名列表，然后可以使用这些计算机名来调用另一个powershell命令。
手动流程：
$Type1Machines=\"Machine1\",\"Machine2\",\"Machine3\",\"Machine4\"
Invoke-command {Powershell.exe C:\\myscript.ps1 Type1} -computername $Type1Machines
<Servers>
<Type1>
<Machine><Name>Machine1</Name> <MachineOS>WinXP</MachineOS></Machine>
<Machine><Name>Machine2</Name> <MachineOS>WinServer2003</MachineOS></Machine>
<Machine><Name>Machine3</Name> <MachineOS>WinServer2003</MachineOS></Machine>
<Machine><Name>Machine4</Name><MachineOS>WinServer2003</MachineOS></Machine>
</Type1>
</Servers>
#TypeInformation will be pass as an argument to the final script
$typeinformation = \'Type1\'
$global:ConfigFileLocation =\"C:\\machineinfo.xml\"
$global:ConfigFile= [xml](get-content $ConfigFileLocation)
$MachineNames = $ConfigFile.SelectNodes(\"Servers/$typeinformation\")
$MachineNames
Machine
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{Machine1, Machine2, Machine3, Machine4}
没有找到相关结果
已邀请:
3 个回复
悲帽慑彤电
[string[]]$arr = @() # declare empty array of strings $ConfigFile.SelectNodes(\"/Servers/$typeInformation/Machine\") | % {$arr += $_.name}抢垢洛韧
[string[]]$arr = @() # declare empty array of strings $ConfigFile.SelectNodes(\"/Servers/$typeInformation/Machine\") | % {$arr += $_.name}$typeInformation = \'Type1\' $arr = ($ConfigFile.Servers.\"$typeInformation\".Machine | % { $_.Name }) -join \',\'$typeInformation = \'Type1\' $arr = ($ConfigFile | Select-Xml \"/Servers/$typeInformation/Machine/Name\" | % { $_.Node.\'#text\' }) -join \',\'马口
#TypeInformation will be pass as an argument to the final script $typeinformation = \'Type1\' $global:ConfigFileLocation =\"C:\\machineinfo.xml\" $global:ConfigFile= [xml](get-content $ConfigFileLocation) $Machines = $ConfigFile.SelectNodes(\"Servers/$typeinformation/Machine\") foreach($Machine in $Machines) { Write-Host $Machine.name }