C ++指针混乱

#include <iostream>

using namespace std;

int main()
{
    const int x = 10;
    int * ptr;
    ptr = (int *)( &x );    //make the pointer to constant int*
    *ptr = 8;               //change the value of the constant using the pointer.
    //here is the real surprising part
    cout<<\"x: \"<<x<<endl;          //prints 10, means value is not changed
    cout<<\"*ptr: \"<<*ptr<<endl;    //prints 8, means value is changed
    cout<<\"ptr: \"<<(int)ptr<<endl; //prints some address lets say 0xfadc02
    cout<<\"&x: \"<<(int)&x<<endl;   //prints the same address, i.e. 0xfadc02
    //This means that x resides at the same location ptr points to yet 
    //two different values are printed, I cant understand this.

    return 0;
}