如何从python cgi脚本的子过程中捕获错误？
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我正在尝试编写一个Python CGI脚本，该脚本将使用子过程调用sox（一种音频处理程序）。问题是，当我从sox调用中收到错误时，所有程序崩溃，并且从Apache中收到“格式错误的标头”错误。
相关位：
def downsample(in_file, in_location, sox, out_location):
\"\"\" run sox \"\"\"
...
sox = shlex.split(sox)
retcode = subprocess.check_call(sox)
if not retcode == 0:
print \'<b>something went wrong in sox: returned error code \' +\\
retcode + \', but we are continuing anyway...</b>\'
\"\"\"p = subprocess.Popen(sox)
if p.stdout:
print \'<b>something happened in sox: returned \' +\\
p.stdout.read() + \', but we will keep going...</b>\'
if p.stderr:
print \'<b>something happened in sox: returned \' +\\
p.stderr.read() + \', but we will keep going...</b>\'\"\"\"
...
def main():
print \"Content-Type: text/html\\n\\n\"
...
downsample(in_file, in_location, command, out_location)
...
if __name__ == \'__main__\':
main()
Wed Apr 13 10:08:21 2011] [error] [client ::1] sox FAIL formats: can\'t open input file `/tmp/wavs/haha/f.wav\': WAVE: RIFF header not found, referer: http://localhost/~Valkyrie_savage/
[Wed Apr 13 10:08:21 2011] [error] [client ::1] malformed header from script. Bad header=\\x1f\\x8b\\b: downsample.py, referer: http://localhost/~Valkyrie_savage/
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3 个回复
骨乏唯瓜
，以确保输出缓冲区中的所有标头和html均已实际打印。 希望这可以帮助。掀辟髓观粟
import subprocess p = subprocess.Popen(cmd) p.wait() if p.returncode: print \"failed with code: %s\" % str(p.returncode)茶鬼失形
try: retcode = subprocess.check_call(sox) except CalledProcessError: print \'<b>something went wrong in sox: returned error code \' +\\ retcode + \', but we are continuing anyway...</b>\'