每个城市十个最便宜的房间

| 我有3张桌子的房间,酒店,城市,我该如何选择每个城市的十个最便宜的房间及其hotel_id 可以为每个城市执行子查询?
SELECT price, room_id, hotel_id, city_id
    FROM Hotel 
    JOIN  Room USING(hotel_id)
ORDER BY price
LIMIT 10


Scheme
CREATE TABLE `City` (
  `city_id` int(11) NOT NULL AUTO_INCREMENT,
  `city_name` varchar(50) NOT NULL,
  PRIMARY KEY (`city_id`)
) 

CREATE TABLE `Hotel` (
  `hotel_id` int(11) NOT NULL AUTO_INCREMENT,
  `city_id` int(11) NOT NULL,
  `hotel_name` varchar(100) NOT NULL,
   PRIMARY KEY (`hotel_id`),
   CONSTRAINT `Hotel_FK_1` FOREIGN KEY (`city_id`) REFERENCES `City` (`city_id`) ON DELETE CASCADE ON UPDATE CASCADE
)

CREATE TABLE `Room` (
  `room_id` int(11) NOT NULL AUTO_INCREMENT,
  `hotel_id` int(11) NOT NULL,
  `room_name` varchar(255) DEFAULT NULL,
  `room_price1` int(11) DEFAULT NULL,
  PRIMARY KEY (`room_id`),
  CONSTRAINT `Room_FK_1` FOREIGN KEY (`hotel_id`) REFERENCES `Hotel` (`hotel_id`) ON DELETE CASCADE ON UPDATE CASCADE
)
用子查询查询
SELECT 
     r.room_price1, r.room_id, h.hotel_name, c.city_name
FROM Hotel h 
INNER JOIN Room r ON
    h.hotel_id = r.hotel_id
INNER JOIN City c USING(city_id)
WHERE (
   SELECT count(*) from Room as rt
   JOIN Hotel ht using(hotel_id)
   where c.city_id = ht.city_id and rt.room_price1 < r.room_price1 OR (rt.room_price1 = r.room_price1 AND rt.room_id < r.room_id)
) < 3 
ORDER BY c.city_name, h.hotel_id, r.room_price1
如果某些酒店有一些room_price1,则此查询返回多于3行的城市信息,并且我需要每个城市3个唯一的酒店,此查询可以从一个酒店返回3个房间 请尝试使用用户变量
set @num := 0, @type := \'\';
select *
from (
   select r.room_price1 pr, r.room_id, h.hotel_name, c.city_name,
      @num := if(@type = city_id, @num + 1, 1) as row_number,
      @type := city_id as dummy
  from Hotel h
  JOIN Room r USING(hotel_id)
  INNER JOIN City c USING(city_id)
  order by city_name, r.room_price1 asc
) as x where x.row_number <=3;
对于row_number <6(我的初始化数据),此方法返回错误的排序     
已邀请:
那里有很多关于该主题的博客文章。 对我来说最有价值的可能是 Xaprb帖子(有关详细说明,请参见“从每个组中选择前N行”一节) http://www.xaprb.com/blog/2006/12/07/how-to-select-the-firstleastmax-row-per-group-in-sql/ 在您的情况下,这意味着。根据您的需求对该SQL进行建模。
select type, variety, price
from fruits
where (
   select count(*) from fruits as f
   where f.type = fruits.type and f.price < fruits.price
) <= 2;
让我们尝试一下
SELECT 
   r.price, r.room_id, h.hotel_id, h.city_id
FROM Hotel h INNER JOIN Room r ON
  h.hotel_id = r.hotel_id
WHERE (
   select count(*) from Room as rt
   where r.hotel_id = rt.hotel_id and r.price > rt.price
) <= 10;
ORDER BY h.city_id,h.hotel_id,r.price
如您所见,您可以进行子查询以选择所有房间的数量 价格低于当前根的价格,看看是否 计数小于或等于10。 特别要注意我如何改变
f.price < fruits.price
r.price > rt.price
因为在Xaprb的示例中,他选择了N个最便宜的水果 希望能有所帮助。 BTW Stackoverflow并非用于解决作业。您也应该学习一些自己的东西;-)     
我假设表“ 7”引用了它所属的“ 8”
SELECT price, room_id, hotel_id, city_id
    FROM Hotel,Room 
    WHERE Hotel.hotel_id = Room.hotel_id
ORDER BY price GROUP BY city_id
LIMIT 10
    

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