javascript中的Json
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我以前没有使用过json。当我在json响应上使用eval函数时，它给了我
缺少\'] \'的错误。我的json如下
[{\"name\":\"154.jpg\",\"size\":620888,\"type\":\"image\\/jpeg\",\"url\":\"\\/active\\/components\\/com_mtree\\/img\\/listings\\/o\\/Tulips.jpg\",\"thumbnail_url\":\"\\/active\\/components\\/com_mtree\\/img\\/listings\\/s\\/Tulips.jpg\",\"delete_url\":\"\\/active\\/components\\/com_mtree\\/img\\/listings\\/upload.php?file=Tulips.jpg\",\"delete_type\":\"DELETE\"}]
var myObject = eval(\'(\' + data + \')\');
没有找到相关结果
已邀请:
2 个回复
剃摧庭峨僳
泻伴墓荒
var x= \'[{\"name\":\"154.jpg\",\"size\":620888,\"type\":\"image\\/jpeg\",\"url\":\"\\/active\\/components\\/com_mtree\\/img\\/listings\\/o\\/Tulips.jpg\",\"thumbnail_url\":\"\\/active\\/components\\/com_mtree\\/img\\/listings\\/s\\/Tulips.jpg\",\"delete_url\":\"\\/active\\/components\\/com_mtree\\/img\\/listings\\/upload.php?file=Tulips.jpg\",\"delete_type\":\"DELETE\"}]\'; alert(eval(x));