list是另一个列表的子集

| 在Python中,给出了两个配对列表:
listA = [ [1,20], [3,19], [37,11], [21,17] ]
listB = [ [1,20], [21,17] ]
如果listB是listA的子集,如何有效地编写返回True的python函数?哦,[1,20]对等效于[20,1]     
已邀请:
        使用
frozenset
>>> listA = [ [1,20], [3,19], [37,11], [21,17] ]
>>> listB = [ [1,20], [21,17] ]

>>> setA = frozenset([frozenset(element) for element in listA])
>>> setB = frozenset([frozenset(element) for element in listB])

>>> setA
frozenset([frozenset([17, 21]), frozenset([1, 20]), frozenset([11, 37]), frozens
et([19, 3])])
>>> setB
frozenset([frozenset([17, 21]), frozenset([1, 20])])

>>> setB <= setA
True
    
        只是为了提供替代方法,也许使用元组和集合更有效:
>>> set(map(tuple,listB)) <= set(map(tuple,listA))
True
    

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