AJAX和PHP问题！
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我有一个PHP页面，该页面将从downloads.nl收集mp3链接。结果转换为XML并呈现良好。
当我尝试使用Ajax读取XML时，会出现问题。这些文件位于同一域中，这真让我感到困惑。这是我的PHP搜寻器。
<?php
header(\"Content-type: text/xml\");
$artistname = $_GET[\'artistname\'];
$trackname = $_GET[\'trackname\'];
$newartistname = str_replace(\" \",\"+\",$artistname);
$newtrackname = str_replace(\" \",\"+\",$trackname);
$target_url = \"http://www.downloads.nl/results/mp3/1/\".$newartistname.\"+\".$newtrackname;
$userAgent = \'Googlebot/2.1 (http://www.googlebot.com/bot.html)\';
error_reporting(0);
// make the cURL request to $target_url
$ch = curl_init();
curl_setopt($ch, CURLOPT_USERAGENT, $userAgent);
curl_setopt($ch, CURLOPT_URL,$target_url);
curl_setopt($ch, CURLOPT_FAILONERROR, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_AUTOREFERER, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
$html= curl_exec($ch);
if (!$html) {
echo \"<br />cURL error number:\" .curl_errno($ch);
echo \"<br />cURL error:\" . curl_error($ch);
exit;
}
// parse the html into a DOMDocument
$dom = new DOMDocument();
@$dom->loadHTML($html);
// grab all the on the page
$xpath = new DOMXPath($dom);
$hrefs = $xpath->evaluate(\"/html/body//a\");
echo \'<?xml version=\"1.0\"?>\';
echo \'<downloads>\';
echo \'<trackname>\'.$newartistname.\"+\".$newtrackname.\'</trackname>\';
for ($i = 0; $i < $hrefs->length; $i++) {
$href = $hrefs->item($i);
$url = $href->getAttribute(\'href\');
if(strpos($url, \".cgi\")){
echo \'<link>http://downloads.nl\'.htmlspecialchars($url,ENT_QUOTES).\'</link>\';
}
}
echo \'</downloads>\';
?>
function getDownloadLink(artistname,trackname){
var xmlhttp4;
if (window.XMLHttpRequest){
xmlhttp4 = new XMLHttpRequest();
}
else{
xmlhttp4 = new ActiveXObject(\"Microsoft.XMLHTTP\");
}
xmlhttp4.onreadystatechange=function(){
alert(xmlhttp4.readyState);
if (xmlhttp4.readyState==4 && xmlhttp4.status==200){
try{
var downloadlink = xmlhttp4.responseXML.documentElement.getElementsByTagName(\"downloads\");
for (var i=0;i<downloadlink.length;i++){
alert(i);
}
}
catch(er){
alert(xmlhttp4.responseText);
}
}
else{
alert(\"ReadyState: \"+xmlhttp4.readyState+\" Status: \"+xmlhttp4.status);
}
}
xmlhttp4.open(\"GET\",\"http://localhost/bone/searchmusic.php?artistname=\"+artistname+\"&trackname=\"+trackname,true);
xmlhttp4.send(null);
}
没有找到相关结果
已邀请:
2 个回复
屉杆绊
<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Strict//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd\"> <html xmlns=\"http://www.w3.org/1999/xhtml\" xml:lang=\"en\" lang=\"en\"> <head> <title>Test</title> <meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\"/> <script src=\"https://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js\" type=\"text/javascript\"></script> <script type=\"text/javascript\"> $(function(){ $(\'.getMp3\').click(function() { var artist = $(\'.artist\', this).text(); var track = $(\'.track\', this).text(); getDownloadLink(artist, track); }); function getDownloadLink(artist, track) { $.ajax({ url:\'downloads.xml\', dataType:\'xml\', success: function(xml) { $(xml).find(\'link\').each(function() { $(\'#results\').append(\'<li><a href=\"\'+$(this).text()+\'\">track</a></li>\'); }); } }); } }); </script> </head> <body> <p> <a href=\"#\" class=\"getMp3\">Get <span class=\"artist\">Lady GaGa</span> - <span class=\"track\">Bad Romance</span> tracks</a> </p> <ul id=\"results\"></ul> </body> </html>该代码实际上并没有使用演出者和曲目，但我添加了它们以使您了解其工作方式。梦话快家腹
function getDownloadLink(artist, track) { $.ajax({ url:\'http://localhost/bone/searchmusic.php?artistname=\'+artist+\'&trackname=\'+track, dataType:\'xml\', success: function(xml) { $(xml).find(\'link\').each(function() { $(\'#download\').append(\'<li><a href=\"\'+$(this).text()+\'\">track</a></li>\'); }); } }); } </script>