得到具有关系的两列
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我和Jobeet学习Symfony和主义。我想添加一些修改。
默认值为:
http://www.symfony-project.org/jobeet/1_4/Doctrine/zh/03
JobeetCategory:
actAs: { Timestampable: ~ }
columns:
name: { type: string(255), notnull: true, unique: true }
JobeetJob:
actAs: { Timestampable: ~ }
columns:
category_id: { type: integer, notnull: true }
(...)
relations:
JobeetCategory: { onDelete: CASCADE, local: category_id, foreign: id, foreignAlias: JobeetJobs }
如果我去表格(创建新的),我有:
http://www.symfony-project.org/images/jobeet/1_4/03/job.png
类别ID-选择列表
//BaseJobeetJobForm.class.php:
\'category_id\' => new sfWidgetFormDoctrineChoice(array(\'model\' => $this->getRelatedModelName(\'JobeetCategory\'), \'add_empty\' => false)),
//sfFormDoctrine.class.php:
protected function getRelatedModelName($alias)
{
$table = Doctrine_Core::getTable($this->getModelName());
if (!$table->hasRelation($alias))
{
throw new InvalidArgumentException(sprintf(\'The \"%s\" model has to \"%s\" relation.\', $this->getModelName(), $alias));
}
$relation = $table->getRelation($alias);
return $relation[\'class\'];
}
我该怎么做:
JobeetCategory:
actAs: { Timestampable: ~ }
columns:
name: { type: string(255), notnull: true, unique: true }
nametwo: { type: string(255), notnull: true, unique: true }
JobeetJob:
actAs: { Timestampable: ~ }
columns:
category_id: { type: integer, notnull: true }
nametwo_id: { type: integer, notnull: true }
(...)
relations:
JobeetCategory: { onDelete: CASCADE, local: category_id, foreign: id, foreignAlias: JobeetJobs }
JobeetCategory: { onDelete: CASCADE, local: nametwo_id, foreign: id, foreignAlias: JobeetJobsTwo }
我如何以\“ nametwo \”形式显示?我将列出两个列表选项(category_id(已经)和nametwo_id :)
没有找到相关结果
已邀请:
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厦惫