PHP：如何检测/解析rss / feed XML中的所有TAG？
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我正在从样本中测试rss feed阅读器。
它用：
$xmlDoc = new DOMDocument();
$xmlDoc->load($url);
$items = $xmlDoc->getElementsByTagName(\'item\');
for ($i=0; $i < $items->length; $i++) {
$item_title = $items->item($i)->getElementsByTagName(\'title\')->item(0)->childNodes->item(0)->nodeValue;
$item_link = $items->item($i)->getElementsByTagName(\'link\')->item(0)->childNodes->item(0)->nodeValue;
$item_desc = $items->item($i)->getElementsByTagName(\'description\')->item(0)->childNodes->item(0)->nodeValue;
}
getElementsByTagName(\'date\')
Fatal error: Call to a member function item() on a non-object
没有找到相关结果
已邀请:
1 个回复
babsoft
$indent = 0; $tab = 4; function indent($indent){ $r = \"\"; for($i=0;$i<$indent;$i++) $r .= \" \"; return $r; } function parseNode($node){ global $indent,$tab; if(!$node->hasChildNodes()) return; $indent += $tab; // if($note->tagName == \"item\") do something special echo indent($indent).\"<\".$note->nodeName.\">\"; foreach ($node->childNodes as $c) parseNode($c); echo indent($indent).\"</\".$note->nodeName.\">\"; $indent -= $tab; } $xmlDoc = new DOMDocument(); $xmlDoc->load($url); parseNode($xmlDoc);