在Android上用“手机号码”查询联系人的最快方法
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我需要从设备及其电话号码中获取所有联系人的明确列表。但是，等等...我们知道某些联系人可能分配了多个号码，这完全取决于每个用户如何存储他的联系人。这是我的工作：
ContentResolver cr = context.getContentResolver();
Uri uri = ContactsContract.Contacts.CONTENT_URI;
String[] projection = new String[] { ContactsContract.Contacts._ID, ContactsContract.Contacts.DISPLAY_NAME };
String selection = ContactsContract.Contacts.HAS_PHONE_NUMBER + \" = \'1\'\";
String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + \" COLLATE LOCALIZED ASC\";
ArrayList<user> contacts = new ArrayList<user>();
Cursor users = a.managedQuery(uri, projection, selection, null, sortOrder);
while (users.moveToNext()) {
user u = new user();
u.PhoneId = users.getInt(users.getColumnIndex(ContactsContract.Contacts._ID));
u.Name = users.getString(users.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
String homePhone = \"\", cellPhone = \"\", workPhone = \"\", otherPhone = \"\";
Cursor contactPhones = cr.query(Phone.CONTENT_URI, null, Phone.CONTACT_ID + \" = \" + u.PhoneId, null, null);
while (contactPhones.moveToNext()) {
String number = contactPhones.getString(contactPhones.getColumnIndex(Phone.NUMBER));
int type = contactPhones.getInt(contactPhones.getColumnIndex(Phone.TYPE));
switch (type) {
case Phone.TYPE_HOME: homePhone = number; break;
case Phone.TYPE_MOBILE: cellPhone = number; break;
case Phone.TYPE_WORK: workPhone = number; break;
case Phone.TYPE_OTHER: otherPhone = number; break;
}
}
u.Phone = ((cellPhone!=\"\") ? cellPhone : ((homePhone!=\"\") ? homePhone : ((workPhone!=\"\") ? workPhone : otherPhone)));
}
return contacts;
没有找到相关结果
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1 个回复
筷啸够对铅
Cursor contactPhones = cr.query(Phone.CONTENT_URI, null, Phone.CONTACT_ID + \" = \" + u.PhoneId, null, null);Cursor contactPhones = cr.query(Phone.CONTENT_URI, null, Phone.CONTACT_ID + \" =? \", new String[] { Integer.toString(u.PhoneId) }, null);的Javadoc重申了以下指导： 使用问号参数标记（例如\'phone =？\'）代替 选择参数中的显式值，以便查询 仅在那些值不同的情况下，缓存才会被识别为相同 目的。