验证PHP中的Select Drop Down Array
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我可以通过以下方式在表单上生成状态下拉列表：
$states = array(\'State\', \'Alabama\', \'Alaska\', \'Arizona\', \'Arkansas\');
echo \"<select name=\'choose_state\'>\\n\";
foreach ($states as $key => $state)
{echo \"<option value=\'$key\'>$state</option>\\n\";}
echo \"</select>\";
没有找到相关结果
已邀请:
3 个回复
室邢
$chosen_state = null; if (array_key_exists(\'choose_state\', $_POST)) { $choose_state = $_POST[\'choose_state\']; if (array_key_exists($choose_state, $states) && $choose_state > 0) { // Value does actually exist in array and is not item 0. $chosen_state = $states[$chose_state]); } }犀寺扦
中... 尝试这个：$max = sizeof($states) - 1; // this is the number of possible values that you have, minus the default if($state_key != 0 && $state_key > 0 && $state_key < $max) { // do whatever here, you\'ve got good data at this point }揽芳僵迷仇
$selectedindex = $_POST[\"choose_state\"]; if($selectedindex == 0) { echo \"Default item has been selected\"; } else{ echo \"Other than default item has been selected \"; //you can do further validation here for selected item //is in between 0 and 5 if you need to do so }