是否有一个等效于XmlWriter.WriteRaw的XElement？

XElement.Parse()

XElement e = new XElement(\"root\",
    new XElement(\"child\",
        XElement.Parse(\"<big><blob><of><xml></xml></of></blob></big>\"),
        new XElement(\"moreXml\")));

XElement.Parse

var d = new XElement(root, XML_PLACEHOLDER);
var s = d.ToString().Replace(XML_PLACEHOLDER, child);

child

Parse

void Main()
{
    // testing:
    // * https://stackoverflow.com/questions/1414561/how-to-add-an-existing-xml-string-into-a-xelement
    // * https://stackoverflow.com/questions/16586443/adding-xml-string-to-xelement
    // * https://stackoverflow.com/questions/587547/how-to-put-in-text-when-using-xelement
    // * https://stackoverflow.com/questions/5723146/is-there-an-xelement-equivalent-to-xmlwriter-writeraw

    var root = \"root\";
    var childContents = \"<name>Fname</name><age>23</age><sex>None of your business</sex>\";
    var child = \"<child>\" + childContents + \"</child>\";

    parse(root, child, true);
    replace(root, child, true);

// this fails, per https://stackoverflow.com/questions/16586443/adding-xml-string-to-xelement
try {
        parse(root, childContents, true);
    } catch(Exception ex) {
        ex.Dump();
    }
// this works, but again, you don\'t get the pretty formatting
    try {
        replace(root, childContents, true);
    } catch(Exception ex) {
        ex.Dump();
    }

    \"Xml Parsing\".Vs(new [] { \"parse\", \"replace\" }
        , n => parse(root, child, false)
        , n => replace(root, child, false)
    );
}

// Define other methods and classes here
void parse(string root, string child, bool print) {
    var d = new XElement(root, XElement.Parse(child));
    var s = d.ToString();
    if(print) s.Dump(\"Parse Result\");
}

const string XML_PLACEHOLDER = \"##c##\";
void replace(string root, string child, bool print) {
    var d = new XElement(root, XML_PLACEHOLDER);
    var s = d.ToString().Replace(XML_PLACEHOLDER, child);
    if(print) s.Dump(\"Replace Result\");
}

Vs